Question

What is the equation for the hyperbola shown?

Answer 1

Answer:

The answer to your question is    $\frac{x^{2}}{60^{2}} - \frac{y^{2}}{11^{2}} = 1$

Step-by-step explanation:

Data

From the graph

Horizontal hyperbola

Center (0, 0)

a = 60     a is the distance from the Center to the Vertex

b = 11       b is the distance from the Center to the endpoint of the conjugate

               axis.

The Equation for a horizontal hyperbola

                $\frac{(x- h)^{2} }{a^{2}} - \frac{(y - k)^{2}}{b^{2}} = 1$

h = 0, k = 0

-Substitution

                $\frac{x^{2}}{60^{2}} - \frac{y^{2}}{11^{2}} = 1$

Answer 2

Answer:

Option 1

Step-by-step explanation:

(x - 0)²/60² - (y - 0)²/11² = 1

x²/60² - y²/11² = 1