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Alik [6]
3 years ago
6

Consider the line y=5/7x+7. Find the equation for the line that is parallel to the line and passes through the point (-5,-2). Fi

nd the equation for the line that is perpendicular to the line and passes through the point (-5,-2).
Mathematics
1 answer:
Nata [24]3 years ago
6 0
The parallel line:
y = mx + c
y = 5/7x + 7

Gradient of parallel line = 5/7

y = mx + c
y = 5/7x + c
-2 = (5/7 x -5) + c
-2 = -25/7 + c
-2 + 25/7 = c
c = 11/7

y = 5/7x + 11/7

The perpendicular line
y = mx + c
y = 5/7x + c
m = 5/7

Gradient of perpendicular line = -1/(5/7) = -7/5

y = mx + c
y = -7/5x + c
-2 = (-7/5 x -5) + c
-2 = 7 + c
-2 - 7 = c
c = -9

y = -7/5x - 9
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The graphs of y = f(x) and y = g(x) are shown on the coordinate plane below. If g(x) = k* f(x), what is the value of k?
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Step-by-step explanation:

Using slope intercept form:

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As per the statement:

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First find f(x):

Consider two points on y=f(x) are:

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then;

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Substitute the point (0, -3) to solve for b:

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Similarly for g(x):

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then;

\text{Slope(m)} = \frac{y_2-y_1}{x_2-x_1}

then;

m = \frac{-2-6}{2-0}=\frac{-8}{2} =-4

then;

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6= -4(0)+b

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then we get an equation:

y = g(x) = -4x+6

It is given that: If g(x) = k* f(x)

Solve for k:

-4x+6 = k(2x-3)

⇒-4x+6 = 2kx-3k

on comparing both sides we have;

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⇒-2k = -4

Divide both sides by -2 we have;

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or

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⇒k = -2

Therefore, the value of k is, -2

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