Consider the line y=5/7x+7. Find the equation for the line that is parallel to the line and passes through the point (-5,-2). Fi
nd the equation for the line that is perpendicular to the line and passes through the point (-5,-2).
1 answer:
The parallel line:
y = mx + c
y = 5/7x + 7
Gradient of parallel line = 5/7
y = mx + c
y = 5/7x + c
-2 = (5/7 x -5) + c
-2 = -25/7 + c
-2 + 25/7 = c
c = 11/7
y = 5/7x + 11/7
The perpendicular line
y = mx + c
y = 5/7x + c
m = 5/7
Gradient of perpendicular line = -1/(5/7) = -7/5
y = mx + c
y = -7/5x + c
-2 = (-7/5 x -5) + c
-2 = 7 + c
-2 - 7 = c
c = -9
y = -7/5x - 9
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Answer:
254.47
Step-by-step explanation:
A= 3.14 x r²
A = 3.14 x 9
A = 254.47
Hope this helps
D is the right answer you just have to minus
about 200 pounds would be your anwser