Question

I need help with number 38 and 39 if anyone could help.

Answer 1

Answer:

Part 1.

The correct option of 38 question is B which is be the smaller size.

Explanation:

As the cell is suspended in salt solution which is hyper tonic as compared to cell.

And salt ions are also not allowed to enter the cell, so the consequence will be the movement of water from cell to salt solution to make cell equal to salt solution.

So the cell will shrink making cell of smaller size.

Part 2.

The correct option of 39 question is option B which is cell B will swell more than cell A.

Explanation:

• Actually here swelling means the size of cells.
• At the end the size of cell B will be more than the size of cell A. Because the cell A is placed in less concentrated solution than the cell B.
• First glucose will diffuse to cell making cell hypotonic and after that water moves in cell by osmosis.
• Water always move from high concentration to low concentration.
• As in cell A low amount of glucose and water will move in cell than Cell B.
• Hence Cell b will swell more than A.

Answer 2

Answers

38. (b) be smaller in size, (The cell 0.5% salt placed in a hypertonic solution of 1.5% salt)

39. (a) cell A will swell more than cell B

Explanation

The process where water moves across a membrane is called osmosis. Salt solution triggers osmosis by attracting the water and making it to move towards it, across the membrane. If the concentration of the salt inside a cell is the same as that concentration outside the cell, the water level will stay the same and there will be no change in shapes of the cells because they are placed in an isotonic solution. A cell cannot loose or gain water when placed in an isotonic solution.

The movement of water in a cell occurs towards the highest solute concentration. If a cell is in a hypertonic solution (> 5% glucose) solution, the water will move from the lower concentration of solute to the region with the highest solute concentration to maintain equilibrium of osmotic pressure. Cell B that is placed in a 5% glucose will lose more water and its size will be smaller than that of cell A because it would have wilted more than cell A which was placed in a 2% glucose solution.