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3 years ago

Find the area of triangle ABC. Give your answer to 1 decimal place. Sine rule.

Mathematics

1 answer:

laiz [17]3 years ago

4 0

Answer:

Solution,

In ∆ ABC

< A + <B + < C = 180°

or, 72 + 59 + <C = 180°

or, 131 + <C = 180°

or, <C = 180 - 131

< C = 49

Area of ∆ABC = 1/2 ab sin C

= 1/2 * 12 * 7 * sin 49

= 42 * sin 49

= 31.7 ( approximately)

Hope this helps...

Good luck on your assignment...

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fiasKO [112]

Answer: $\sqrt{65}$

Step-by-step explanation:

<u>Concept:</u>

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The distance formula is the formula, which is used to find the distance between any two points.

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3 years ago

Which of the following are exterior angles? Check all that apply.

Naily [24]

Answer:

Exterior angles are <4 and <6

Step-by-step explanation:

From the figure we can see a triangle and its some exterior angles.

Exterior angles means that angles on the out side.

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From the figure we get exterior angles are,

<4 and <6

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4 0

3 years ago

What is the volume of a triangular pyramid that has a base area of 8.2 square centimeters and a height of 4

Harman [31]

Answer:

$\boxed {\boxed {\sf V \approx 10.9 \ cm^3}}$

Step-by-step explanation:

The volume of a triangular pyramid can be found using the following formula:

$V=\frac{1}{3} A_b\times h$

Basically, we have to multiply 1/3, the height, and the base area.

We know that the base area is 8.2 square centimeters and the height is 4 centimeters.

$A_b=8.2 \ cm^2 \\h= 4 \ cm$

Substitute the values into the formula.

$V=\frac{1}{3} (8.2 \ cm^2)\times (4 \ cm)$

Multiply 8.2 square centimeters and 4 centimeters.

8.2 cm² * 4 cm= 32.8 cm³

$V=\frac{1}{3} (32.8 \ cm^3)$

Multiply 1/3 and 32.8 cubic centimeters.

$V= 10.9333333 \ cm^3$

Round to the nearest tenth.

The 3 in the hundredth place tells us to leave the 9 in the tenth place.

$V \approx 10.9 \ cm^3$

The volume of the triangle pyramid is about 10.9 cubic centimeters.

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