Answer:
10 and 40 I think maybe?
Step-by-step explanation:
I hope this is correct if not I am so so so so so so sorry
Answer:
To make estimates, we usually round the numbers the nearest integer.
Since 1.9 is closest to 2 than it is to 1, the nearest integer of 1.9 is 2.
Similarly, since 4.4 is closest to 4 than it is to 5, the nearest integer of 4.4 is 4.
Now, to estimate the area of the farm, we are going to multiply our two integers:
Estimated Area of the Farm= x
Since 8 is between 4 and 10, we can conclude that the best estimate of the area of the farm is: between 4 and 10
Step-by-step explanation:
Answer:
$6.48
Step-by-step explanation:
It would be $6.48 because 1.60 times 4 1/2 is 7.2 and if you do 10% of 7.2 you get B.
I found this --The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.
Answer:
a) 0.4121
b) $588
Step-by-step explanation:
Mean μ = $633
Standard deviation σ = $45.
Required:
a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = $646
z = 646 - 633/45
z = 0.22222
Probability value from Z-Table:
P(x<646) = 0.58793
P(x>646) = 1 - P(x<646) = 0.41207
≈ 0.4121
b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)
Converting 0.16 to percentage = 0.16 × 100% = 16%
The z score of 16%
= -0.994
We are to find x
Using z score formula
z = (x-μ)/σ
-0.994 = x - 633/45
Cross Multiply
-0.994 × 45 = x - 633
-44.73 = x - 633
x = -44.73 + 633
x = $588.27
Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16
is $588
