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pishuonlain [190]
3 years ago
6

Please help and show work !!!

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0
C = 13
from Pythagoras's theorem
C^2 = A^2 + B^2
= 5^2 + 12^2
= 24 + 144
= 169
then C = √ 169 = 13
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Express the series using sigma notation. 6 + 9 + 12 + 15.<br><br> a<br> b<br> c<br> d
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Answer:

Option (d) is correct.

6 + 9 + 12 +15 = \sum_{k=1}^{4}(3k+3)

Step-by-step explanation:

Consider the given series expansion 6 + 9 + 12 +15.

since we have to write in series form of 3.

We first write each term of given series in term of 3k or 3k+3

6 can be written as 3(2) or 3(1)+3

9 can be written as 3(3) or 3(2)+3

12 can be written as 3(4) or 3(3)+3

15 can be written as 3(5) or 3(4)+3

Thus, we can write the given series as ,

\sum_{k=2}^{5}3k or  \sum_{k=1}^{4}(3k+3)

Since, we have options to choose.

From the given option (d) matches our result.

So,  6 + 9 + 12 +15 = \sum_{k=1}^{4}(3k+3)


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