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Bad White [126]
2 years ago
5

Which transformation maps the pre-image to the image?

Mathematics
1 answer:
Ede4ka [16]2 years ago
4 0

Answer:

Reflection

Step-by-step explanation:

Because reflecting yourself in a mirror means pre image to image

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HELP PLEASE! I WILL GIVE BRAINLIEST
rusak2 [61]

Answer:

13.89

Step-by-step explanation:

A^2+B^2=C^2

7^2+12^2=C^2

193 = C^2

193 square root = 13.89

6 0
3 years ago
The perpendicular bisector of side AB of ∆ABC intersects side AB at point D and BC at point E. If m∠CAB = 82° and m∠C = 68°, fin
riadik2000 [5.3K]
Check the picture below.

now, an angle bisector I assume, since it intersects the opposite segment at D and then at E.  An angle bisector cuts an angle in two equal halves, so if ∡CAB is 82°, that just means that ∡CAE is one of those halves, or 41°.

8 0
3 years ago
The scale factor of the dimensions of two similar wood floors is 5 ​: 3. It costs ​$144 to refinish the smaller wood floor. At t
Eva8 [605]

Answer: 240

Step-by-step explanation:

144/3 = 48

5x48= 240

6 0
3 years ago
Find the unit rate: $23.96 for 4 pounds
Volgvan

Answer:

5.99 dollars per pound

Step-by-step explanation:

Convert to a decimal by dividing the numerator by the denominator.

5 0
3 years ago
Read 2 more answers
Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker
LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

<u><em>Let X = Math scores on the SAT exam</em></u>

So, X ~ Normal(\mu=514,\sigma^{2} =118^{2})

The z score probability distribution for normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma} ~  N(0,1)

where, \mu = population mean score = 514

           \sigma = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

       P(455 < X < 573) = P(X < 573) - P(X \leq 455)

       P(X < 573) = P( \frac{X-\mu}{\sigma} < \frac{573-514}{118} ) = P(Z < 0.50) = 0.69146

       P(X \leq 2.9) = P( \frac{X-\mu}{\sigma} \leq \frac{455-514}{118} ) = P(Z \leq -0.50) = 1 - P(Z < 0.50)

                                                         = 1 - 0.69146 = 0.30854

<em>The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.</em>

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = <u>0.38292</u>

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0
3 years ago
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