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3 years ago

How do you do y divided by 9=12?

Mathematics

2 answers:

mina [271]3 years ago

8 0

1=9/12
1=3/4
if you want this

Airida [17]3 years ago

4 0

If you refer to y/9=12 the answer is:
y/9=12
y=12*9
y=108

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X is inversely proportional to y, and x = 18 when y = 4. Write an equation relating the two

Alenkasestr [34]

Answer:

$xy=72$

Step-by-step explanation:

If x is inversely porportionaly to y, then for some constant k,

$x = \frac{k}{y}\\xy=k$

Since y is 4 when x = 18, k is equal to 4*18=72, so the equation is:

$xy=72$

8 0

3 years ago

What is 10% of 1/4 please help and explain

makvit [3.9K]

10/100=0.1
1/4=0.25
0.1*0.25=0.025

5 0

3 years ago

Read 2 more answers

Kona wants to bake at most 30 loaves of banana bread and nut bread for a bake sale. Each loaf of banana bread sells for $2.50, a

frutty [35]

x+y≤30 and 2.50x+2.75y≥44 are the inequalities that model given situation.

Step-by-step explanation:

Given,

Number of banana breads and nut breads to bake = at most 30

At most 30 means the amount cannot exceed 30.

Selling price of each banana bread = $2.50

Selling price of each nut bread = $2.75

Amount to make = $44 at least

At least 44 means that the amount cannot be less than 44.

Let,

x represent the number of loaves of banana bread to be sold

y represent the number of loaves of nut bread to be sold

x+y≤30

2.50x+2.75y≥44

x+y≤30 and 2.50x+2.75y≥44 are the inequalities that model given situation.

Keywords: linear inequalities, addition

Learn more about linear inequalities at:

#LearnwithBrainly

5 0

3 years ago

At Rose State College Allison Wells received the following grades her accounting class 93, 60, 78, 89 ,78 and 82 Allison's instr

Lunna [17]

so you drop the 60.
$93 + 78 + 89 + 78 + 82 = 420$
$420 \div 5 = 84$

so the answer is 84

7 0

3 years ago

I really need help quick

Natali [406]

Answer:

$\sf x=2+\sqrt{6},\:x=2-\sqrt{6}$

Explanation:

$\sf y = x^2 -4x$

given that y = 2

$\sf x^2 -4x = 2$

$\sf x^2 -4x -2 = 0$

using quadratic formula:

$\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ \ when \ ax^2 + bx + c = 0$

$\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}$

$\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}$

$\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}$

in decimals:

$\rightarrow \sf x=4.45 , \ -0.45$

5 0

2 years ago