Answer:
5AB + 40 = +2
Step-by-step explanation:
IN FIRST BLANK (5AB)
SECOND BLANK (40)
Step-by-step explanation:
find the Lcm of 15 and 10 which is 30
multiply the 2fractions by the LCM
8/15*30=16
3/10*30=9
add the products and put them all over the Lcm
(16+9)/30
=25/30 which is equivalent to 5/6 when you divide both the numerator and the denominator by 5
5y=4/5+3/5
5y=7/5: 5
y= 7/35
y= 1/5
Given:
Reflect square JKLM with J(1, 4), K(6, 5), L(7, 0) and M(2, -1) in the y-axis.
To find:
The coordinates of M'.
Solution:
We have, M(2, -1) .
If a figure reflected over the y-axis then
Using this rule, we get
Therefore, the coordinates of point M' are (-2,-1).
Answer:
b=2
Step-by-step explanation:
we have
9x+12y=21 -----> equation A
6x+8y=7b ----> equation B
we know that
If the system of equations have an infinite number of solutions then the equation A must be equal to the equation B
Multiply equation B by 1.5 both sides
1.5*[6x+8y[=7b*1.5
9x+12y=10.5b ----> equation C
Compare equation A and equation C
9x+12y=21 -----> equation A
9x+12y=10.5b ----> equation C
For the equations to be equal it must be fulfilled that
21=10.5b
solve for b
b=21/10.5
b=2