3 years ago

Please this is due in 10 mins!

Mathematics

1 answer:

MrRa [10]3 years ago

8 0

It c so you see I can help you

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Lane reads 25 pages in 30 seconds. If lane reads 200 pages at the same rate how long will it take her

olga55 [171]

30÷25=1.2
she reads 1 page in 1.2 seconds
there fore 1.2×200=240
the answer is 240 seconds

8 0

3 years ago

Read 2 more answers

60 is 5 times greater than k expression

Alik [6]

60=5k
Is the equation because the word 'is' means equals, so we add an equal sign after the 60. "Five times greater" simply means multiply so we multiply 5 and k.
Then to solve the equation, you would need to divide both sides by 5 to isolate the variable
60/5=5k/5
12=k
I hope this helped!

6 0

3 years ago

One jar filled with honey weighs 120 grams and one empty jar with half filled honey jar weighs 150 grams what is the weight of t

VMariaS [17]

Answer:

90 grams

Step-by-step explanation

Full = 120

half filled + empty = 150

half of 120 = 60

Therefore, a jar weighs 150 - 60

= 90 grams

5 0

2 years ago

Quadrilateral ABCD is similar to quadrilateral EFGH the length of the three longest side in quadrilateral ABCD are 24 feet 16 fe

Triss [41]

Check the picture below

solve for "x"

since we know the two smallest sides for EFGH are 9 and 18, 9 is the smallest of all, and 18 is the next small

thus, for the the quadrilateral ABCD, the smallest is "x" and the next small is given, is 12, since that's smaller than 16 or 24

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3 years ago

Use your graphing calculator to determine if the equation appears to be an identity or not by graphing the left expression and r

andrezito [222]

Answer:

$(sec x)+(cos x)=(tan x)*(sin x)\\identities\\(sec x)= 1/cos x\\(tan x)=sin x/cos x\\\\and\\(cos x)^{2}+(sin x)^{2}=1\\(cos x)^{2}=1-(sin x)^{2}\\\\(1/cos x )+(cos x) = (sin x)*(sin x)/(cos x)\\ [(1/cos x)+(cos x)]*(cos x)=(sin x)^{2}\\\\1+(cos x)^{2}=(sin x)^{2}\\1+1-(sin x)^{2}=(sin x)^{2}\\2=2*(sin x)^{2}\\2/2=(sin x)^{2}\\1=(sin x)^{2}\\\\This is not true ,so\\(sec x)+(cos x)\neq (tan x)*(sin x)$

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3 years ago