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Ber [7]
3 years ago
10

What is the zero of g?

Mathematics
1 answer:
Bas_tet [7]3 years ago
6 0
I would help but I can't see the picture very well
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X + 6 = 2x - 8<br> x=<br> solve for x
nata0808 [166]

Step-by-step explanation:

x + 6 = 2x - 8

1. Subtract 2x from both sides

x - 2x + 6 = 2x - 2x - 8

2. Simplify

-x + 6 = -8

3. Now, subtract 6 from both sides

-x + 6 - 6 = -8 - 6

4. Simplify

-x = -14

5. Divide both sides by -1 because you would want the x by itself instead of having -x

-1x/-1 = -14/-1

6. Simplify

x = 14 <------ Answer

Hope that helped!!

~Shane

8 0
3 years ago
What is the slope of the line through(-5,-10) and (-1,5)
Akimi4 [234]
<span> Put the values of above points in the equation of straight </span>line<span> point-</span>slope<span> form m=(y2-y1)/(x2-x1) m=(-</span>5-(-10))/(-1-5) m=(-5+10)/(-6) m=5/-6 m=-5<span>/6. </span>Slope of the line<span> = m = -</span>5<span>/6 so the answer is 5/6</span>
7 0
3 years ago
Read 2 more answers
(12y 2+17y-4)+(9y-13y+3)
IrinaVladis [17]

Answer:

4y+3

Step-by-step explanation:

8 0
3 years ago
Is the relationship linear, exponential, or neither?
kati45 [8]

Answer:

Neither linear nor exponential

Step-by-step explanation:

To check for a linear relationship.  Find slope.

slope=  (-1  -  (-2)) / ( 5 - 2)  = 1/3

check  other points

slope = (1 - (-1) )/ (8 - 5) =  2/3

check more

slope = (4 - 1) / (11 - 8) = 3/ 3 = 1

Nope.

try assuming an exponential:

y = c * (a^x)

-2 =  c* (a^2);    -2/c = a^2

-1 = c *(a ^5);    -1/c = a^5

1 =  c * (a^8),     1/c = a^8

(-2/c)^4 = a^8 = 1/c

16/(c^4) = 1/c

c^3 = 16,  then    a = root (-2/ cube-root(16) )

The change from negative to postive  would not work  for y = c(a^x)

so...

assume   y =  a^x  + k

-2 = a^2  + k

-1 = a^5  + k

...  I would say neither..

6 0
3 years ago
Solve the following system by graphing and identify the point of intersection -5x+2y=-4 2x-y=2
FrozenT [24]

Answer: Point of intersection (0, -2)

Step-by-step explanation:

8 0
1 year ago
Read 2 more answers
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