You know a1.
So find a2, a3, and so on until a7.
a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
Answer:
Step-by-step explanation:
Let (x,y) be midpoint of P(3,4) & Q(5,−2)
Midpoint formula for two points (a,b) and (c,d) is
(x,y) =(
2
a+c
,
2
b+d
).
x=
2
3+5
=4
y=
2
4−2
=1
∴ (x,y)=(4,1)
The answer is 2^12 = 4096.
Look at a tree diagram. With one spin there are two possible outcomes (branches). Every time you spin, each of the branches split into two more branches.
With 12 spins, first there are 2 branches, then 2*2, then 2*2*2, ... In the end it's 2^12
