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3 years ago

Which of the following statements must be true about this diagram? PLEASE HELP

Mathematics

2 answers:

Naddika [18.5K]3 years ago

7 0

Answer:

A is the one that is true

Step-by-step explanation:

Because W is bigger than Z as it has the bigger proportion of the angle :)

scoray [572]3 years ago

5 0

Answer:

Step-by-step explanation:

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In isosceles right triangle ABC, point is on hypotenuse \overline{BC} such that \overline{AD} is an altitude of \triangle ABC an

Dmitriy789 [7]

Answer:

Area of triangle is 25.

Step-by-step explanation:

We have been given an isosceles right triangle

Isosceles triangle is the triangle having two sides equal.

Figure is shown in attachment

By Pythagoras theorem

$BC^2=AC^2+AB^2$

AD is altitude which divides the triangle into two parts

DC=5 implies BC =10 since D equally divides BC

Let AC=a implies AB=a being Isosceles

On substituting the values in the Pythagoras theorem:

$10^2=a^2+a^2$

$100=2a^2$

$\Rightarrow a^2=50$

$\Rightarrow a=\pm5\sqrt{2}$

WE can find area of right triangle by considering height AB and AD

Area of triangle ABC is:

$\frac{1}{2}\cdot BC\cdot AD$ (1)

$\Rightarrow \frac{1}{2}\cdot 10\cdot AD$

And other method of area of triangle is:

$\frac{1}{2}\cdot AB\cdot BC$ (2)

Equating (1) and (2) we get:

$\frac{1}{2}\cdot 10\cdot AD=\frac{1}{2}\cdot a\cdot a$

$\Rightarrow AD=\frac{a^2}{10}$

$\Rightarrow AD=\frac{50}{10}=5$

Using area of triangle is: $\frac{1}{2}\cdot BC\cdot AD$

Now, the area of triangle ABC= $\frac{1}{2}\cdot 5\cdot 10$

$\Rightarrow 25$

4 0

3 years ago

The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of

emmasim [6.3K]

Answer:

The null hypothesis is: $H_{0}: \mu = 100$

The alternative hypothesis is: $H_{a}: \mu > 100$

Step-by-step explanation:

At the null hypothesis, we test if the mean is equal to a certain value.

At the alternate hypothesis, we test if the mean is less than, more than, or different from the value tested at the null hypothesis.

The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of 20 lb.

This means that the null hypothesis is: $H_{0}: \mu = 100$

Could it be that the average tuft strength is above 100 lb?

The world above means that the appropriate alternative hypothesis is: $H_{a}: \mu > 100$

3 0

3 years ago

Difference between purchase book and sales book

tigry1 [53]

A purchase is one where you purchase it and sales is one you sell :)

Hope that helped!

4 0

3 years ago

Read 2 more answers

Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t

andrew11 [14]

Answer:

a) X Freq. Rel Freq.

__________________________

0 7 (7/58) = 0.121

1 10 (10/58)=0.172

2 13 (13/58) =0.224

3 14 (14/58)=0.241

4 6 (6/58)=0.103

5 3 (3/58)=0.052

6 3 (3/58)=0.052

7 1 (1/58) =0.017

8 1 (1/58)=0.017

_________________________

Total 58 1.00

b) $\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862$

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2 2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3 3 3

4 4 4 4 4 4

5 5 5

6 6 6

And we can construct the following table:

X Freq. Rel Freq.

__________________________

0 7 (7/58) = 0.121

1 10 (10/58)=0.172

2 13 (13/58) =0.224

3 14 (14/58)=0.241

4 6 (6/58)=0.103

5 3 (3/58)=0.052

6 3 (3/58)=0.052

7 1 (1/58) =0.017

8 1 (1/58)=0.017

_________________________

Total 58 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

$\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862$

4 0

3 years ago

pls, don't fight like my last one- What is the missing numerator? blank over seven-plus thirteen over fourteen equals one and th

Pavel [41]

Hi!

I'm 90% sure that the answer is: <em>5</em>

Sorry its its wrong!

Hope this helps!

Let me know if you need anymore help!

<em>Yours truly,</em>

<h2><em>~~~PicklePoppers~~~</em></h2>

7 0

3 years ago