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2 years ago

the ratio of red to grern to blue sweets in a packet is 2:3:1. if there are 18 green sweets, how many blue sweets are there??

1 answer:

3 0

If the ratio is 2:3:1

You are looking for y in x:18:y

To get from 2:3:1 you multiply by 3 so your new ratio would be

6:18:3 so there would be 3 blue sweets

You might be interested in

Which is greater thirty six and nine thousandths or four tens

malfutka [58]

Answer:

four tens

Step-by-step explanation:

four tens is greater because:

four tens = 40

thirty six and nine thousandths = 36.009

36.009 < 40

6 0

3 years ago

Put the following equation in standard form and determine the quadratic, linear, and constant coefficients. -3x2 - 8 = 5x - 7

marusya05 [52]

Answer:

-3x² -5x -1 = 0
-3 (quadratic)
-5 (linear)
-1 (constant)

Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

<h3>Standard form</h3>

We can subtract the right-side expression from both sides to get standard form.

-3x² -8 -(5x -7) = 5x -7 -(5x -7)

-3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

-3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

-3x² -5x -1 = 0

<h3>Coefficients</h3>

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

<em>Additional comment</em>

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

8 0

2 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

qwelly [4]

932 in the green box and 9 in the gray box

3 0

3 years ago

Read 2 more answers

PLS HELP ASAP WILL GIVE BRAINLIEST IF RIGHT

Julli [10]

Your answer is 10 for m<5

4 0

3 years ago

The attendance at baseball games at a certain stadium is normally distributed, with a mean of 30,000 and a standard deviation of

lakkis [162]

Answer:

a) 0.964

b) 0.500

c) 0.885

d) $x \geq 32467.5$

e) 0.997

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30000

Standard Deviation, σ = 1500

We are given that the distribution of attendance at stadium is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(attendance is greater than 27,300)

P(x > 27300)

$P( x > 27300) = P( z > \displaystyle\frac{27300 - 30000}{1500}) = P(z > -1.8)$

$= 1 - P(z \leq -1.8)$

Calculation the value from standard normal z table, we have,

$P(x > 27300) = 1 - 0.036 = 0.964 = 96.4\%$

b) P(attendance greater than or equal to 30000)

$P(x > 30000) = P(z > \displaystyle\frac{30000-30000}{1500}) = P(z \geq 0)\\\\P( z \geq 0) = 1 - P(z \leq 0)$

Calculating the value from the standard normal table we have,

$1 - 0.500 = 0.500 = 50\%$

c) P(attendance between 27000 and 32000)

$P(27000 \leq x \leq 32000) = P(\displaystyle\frac{27000 - 30000}{1500} \leq z \leq \displaystyle\frac{32000-30000}{1500}) = P(-2 \leq z \leq 1.33)\\\\= P(z \leq 1.33) - P(z < -2)\\= 0.908 - 0.023 = 0.885 = 88.5\%$