Answer:
5
Step-by-step explanation:
<u>P</u>arenthesis
<u>E</u>xponents
<u>M</u>ultiplication
<u>D</u>ivision
<u>A</u>ddition
<u>S</u>ubtraction
<em><u>Following the order, first is parenthesis:</u></em>
3 · 5 - 2(5)
<em><u>Multiplication:</u></em>
15 - 10
5
Answer:
g(x)= x^2+10x + 24.
Step-by-step explanation:
g(x) = (x + 5)^2 −1
= x^2 + 5x + 5x + 25 - 1
= x^2 + 10x + 24
g(x)= x^2+10x + 24 is your answer.
Hope this helps!
Answer:
11.7
Step-by-step explanation:
use the distance formula known as pythagorem theorem and plug in the x and y values.
The amount of money Ada have initially is $9.25 and this can be determined by forming the linear equation.
Given :
- Ada, Betty, Chris, and David have $45 in total.
- If Ada gets $2 from Betty, Chris triples his money, and David's money is cut by half, four of them have the same amount.
The following steps can be used in order to determine the money Ada have initially:
Step 1 - Let the total money of Ada be 'a', Betty be 'b', Chris be 'c', and David be 'd'.
Step 2 - The linear equation that represents the total money they have is given by:
a + b + c + d + = 45 -- (1)
Step 3 - Now, after Ada gets $2 from Betty, Chris triples his money, and David's money is cut by half, four of them have the same amount of money.
Step 4 - Let the amount of money they all have be 'x' then:
4x = 45 ---- (from equation (1))
x = $11.25
Step 5 - The initial amount of money Ada have is:
x = a + 2
11.25 = a + 2
11.25 - 2 = a
a = $9.25
So, Ada have $9.25 initially.
For more information, refer to the link given below:
brainly.com/question/2263981
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E
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Work Shown
Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A
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Problem 47)
If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago
So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B
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Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
