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tatiyna
3 years ago
15

What does the intersection of two coplanar lines form?

Mathematics
2 answers:
igomit [66]3 years ago
5 0
a plane is the answer
Anuta_ua [19.1K]3 years ago
4 0

a plane

hope this helps :)

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What are the 1st and 3rd quartiles?<br> what is the interquartile range?
FrozenT [24]

Answer:

The first quartile is 5

The third is 8

The interquartile is the difference between the first and third quartile.

The interquartile is 3

Step-by-step explanation:

First, make a list of all the numbers. To find the first quartile, you have to first find the median. The median is the first 7 in the list.

Everything before 7 is the lower percentile of the range.

The firsr quartile is the median of the lower percentile.

The lower list is:

2,3,4,4,5,6,6,6

The median of this list is 5.

The process for finding the third quartile is the same except the list is the higher percentile which is the list of numbers above the median.

7 0
2 years ago
Read 2 more answers
Find an equation of the plane through the point (−1,−5,−2)(−1,−5,−2) with normal vector n=⟨−5,−4,−1⟩n=⟨−5,−4,−1⟩.
Ostrovityanka [42]
Consider this option:
1. given: n(A;B;C)=n(-5;-4;-1) and A(-1;-5;-2)=A(x₀;y₀;z₀).
Common view of equation for a plane is Ax+By+Cz+D=0, where A,B,C,D - numbers.
2. from another side using coordinates of A and normal vector it is possible to make up the equation: A(x-x₀)+B(y-y₀)+C(z-z₀)=0 ⇒ -5(x+1)-4(y+5)-(z+2)=0; ⇒ -5x-4y-z-27=0 or 5x+4y+z+27=0.
7 0
3 years ago
A messenger entered a building on the ground
sp2606 [1]
He first travels 15 floors. He then travels 12 floors, to get to the 3rd floor. He finally travels 35 floors, for a total of 62 floors.
8 0
2 years ago
he puppy weighed 2 pounds when it was born. He has gained weight, but still weighs less than 11 pounds. How much weight could he
Vikentia [17]

Answer:

n=9

Step-by-step explanation:

just did it

4 0
2 years ago
10 points!!! please help :(
daser333 [38]
To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
3 years ago
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