Question

Find the third term of the geometric sequence when a^1=1/4 and r=−2

Answer 1

Answer:

The answer is 1

Step-by-step explanation:

Since the sequence is a geometric sequence

For an nth term in a geometric sequence

$A(n) = a ({r})^{n - 1}$

where n is the number of terms

a is the first term

r is the common ratio

From the question

a = 1/4

r = - 2

Since we are finding the third term

n = 3

So the third term of the sequence is

$A(3) = \frac{1}{4} ({ - 2})^{3 - 1}$

$A(3) = \frac{1}{4}( { - 2})^{2}$

$A(3) = \frac{1}{4} \times 4$

We have the final answer as

A(3) = 1

Hope this helps you