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Eddi Din [679]
3 years ago
7

Find the third term of the geometric sequence when a^1=1/4 and r=−2

Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

<h2>The answer is 1</h2>

Step-by-step explanation:

Since the sequence is a geometric sequence

For an nth term in a geometric sequence

A(n) = a ({r})^{n - 1}

where n is the number of terms

a is the first term

r is the common ratio

From the question

a = 1/4

r = - 2

Since we are finding the third term

n = 3

So the third term of the sequence is

A(3) =  \frac{1}{4}  ({ - 2})^{3 - 1}

A(3) =  \frac{1}{4}(  { - 2})^{2}

A(3) =  \frac{1}{4}  \times 4

We have the final answer as

<h3>A(3) = 1</h3>

Hope this helps you

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What is the circumference of the circle below? (Round your answer to the nearest tenth.)
Yuri [45]

Answer:69.1

Step-by-step explanation:

Circumference=2×π×radius

Circumference=2×22/7×11

Circumference=(2×22×11)/(1×7×1)

Circumference=484/7

Circumference=69.1cm

8 0
4 years ago
The sum of two rational number is 0 and one of them is -4/7,find the other<br>​
Anettt [7]

Answer:

4/7

Step-by-step explanation:

a positive will cancel out the negative number

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4 years ago
1) convert the following percentage into a fraction : 4%
Damm [24]
Any percentage is the number divided by 100. So, 4% is 4/100. That can be simplified to 1/25.
6 0
4 years ago
Read 2 more answers
-8 + (-5) × (-8) - (-6)<br> -3 + (-8) = 2 x4
Lynna [10]

Answer:

Hope it helps

Step-by-step explanation:

A.)-8-5 X -8+6

-13 X -2

+26

B.)-3-8 = 2 X 4

-11≠8

please mark brainliest

5 0
3 years ago
Find the solutions of the following equations by extracting square roots 9x2-16=0 (z-2)2-36=0
natta225 [31]

The solutions of the equation 9x² - 16 = 0is 4/3 and -4/3 and that of the equation (z - 2)^{2}  - 36 = 0 is 8 and -4.

Solving the both quadratic equations by extracting square roots:

9x^{2}  - 16 = 0

⇒ 9x^{2}  = 16                                    

∴ On taking square-root of both sides, we get

\sqrt{9x^{2} } = \sqrt{16}

⇒ 3x = +4 and 3x = -4

⇒ x = 4/3 and x = -4/3

For the equation, (z - 2)^{2}  - 36 = 0, the solution is:

(z - 2)^{2}  - 36 = 0

⇒ (z - 2)^{2}  = 36

∴ On taking square-root of both sides, we get

\sqrt{(z - 2)^{2} }  = \sqrt{36}

⇒ (z - 2) = 6 and (z - 2) = -6

⇒ z = 6 +2 and z = -6 + 2

⇒ z = 8 and z = -4

The solution of the equation 9x^{2}  - 16 = 0 is 4/3 and -4/3.

The solution of the equation (z - 2)^{2}  - 36 = 0 is 8 and -4.

For similar equation, visit here:

brainly.com/question/18397338

#SPJ4

7 0
2 years ago
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