Step-by-step explanation:
The problem statement says λ<1. If this is true, then the cannonball is slower than the boat, and it will never reach the boat. So I assume it's actually λ>1.
If we say t is the amount of time, then the boat travels south a distance of ut, and the cannonball travels a distance of λut.
v = λut
ut = v/λ
Using Pythagorean theorem:
d² + (ut)² > v²
d² + (v/λ)² > v²
λ²d² + v² > λ²v²
λ²d² > (λ² − 1) v²
λ² / (λ² − 1) > (v/d)²
Answer:
The measures of ∠BOC is 25.4° and that of ∠AOB is 15.8°.
Step-by-step explanation:
Given that,
∠AOC = 31°
∠BOC = 2x+10
∠AOB = 4x-15
As we can seen from the figure that,
∠AOC = ∠AOB + ∠BOC
Put all the values,
31 = 4x-15+2x+10
31 = 6x-15
31+15 = 6x
46 = 6x
x = 7.7
∠BOC = 2(7.7)+10 = 25.4°
∠AOB = 4(7.7)-15 = 15.8°
So, the measures of ∠BOC is 25.4° and that of ∠AOB is 15.8°.
Answer:
answer is 33.5
Step-by-step explanation:
1/2m-3/4=16
1/2m=16+3/4
1/2m=64+3/4
1/2m=67/4
m=67/4×2
m=33.5
Answer:
x = 6.5
Step-by-step explanation:
* since it's a triangle ALL the angles inside should give you 180° * Equate everything to 180°
8x + 10x - 10°+ 10x + 8° = 180°( sum of angles on a triangle)
28x - 2° = 180° * group like terms*
28x = 182°
x = 6.5
Answer:
y=14
Step-by-step explanation:
Put the x value where it belongs
y=4(3)+2 Now do the math ( id.k what to say here for the problem other than that lol)
y=12+2
y=14
