Answer:
#include <stdio.h>
void interchangeCase(char phrase[],char c){
for(int i=0;phrase[i]!='\0';i++){
if(phrase[i]==c){
if(phrase[i]>='A' && phrase[i]<='Z')
phrase[i]+=32;
else
phrase[i]-=32;
}
}
}
int main(){
char c1[]="Eevee";
interchangeCase(c1,'e');
printf("%s\n",c1);
char c2[]="Eevee";
interchangeCase(c2,'E');
printf("%s\n",c2);
}
Explanation:
- Create a function called interchangeCase that takes the phrase and c as parameters.
- Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
- If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
- Inside the main function, test the program and display the results.
#1 is A and #2 is B, but I don't know about #3 and #4.
This seems like an opinionated question, I suggest attempting to answer it yourself.
Answer:
I am not sure on this one I am guessing it is True
Explanation:
Answer:
D. Subscriber
Explanation:
Digital Subscriber Line is a family of point-to-point technologies designed to provide high-speed data transmission over traditional telephone lines.
The high speed data transmission property helps to transmit data in a fast and timely manner between two or more points or people during calls, texts and other activities.
