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2 years ago

What programming language supports relational databases?

Computers and Technology

1 answer:

WINSTONCH [101]2 years ago

5 0

A programming language that supports relational databases is SQL (Structured Query Language)

Structured Query Language (SQL), is the principal method for communicating with Relational Databases.

A relational database is a group of data elements that are linked together by predefined connections. These elements are laid up in the form of a series of tables containing columns and rows.

Tables are utilized for storing data about the items that will be displayed in the database.
A column in a database contains a specific type of data, whereas a field records the actual value of an attribute.
The table's rows indicate a collection of linked values for a single item or entity.

Each entry in a database can be assigned a unique identity known as a primary key, and rows from other tables can be linked together via foreign keys. This data may be accessible in a variety of ways without having to reorganize the database tables itself.

Learn more about Relational Databases here:

brainly.com/question/8457395?referrer=searchResults

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3 years ago

For this lab you will write a class to create a user-defined type called Shapes to represent different shapes, their perimeters

maw [93]

<h2>Answer:</h2>

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========= Shape.java ===========

//import the Scanner class

import java.util.Scanner;

public class Shape{

//required fields

private String shape;

private double area;

private double perimeter;

//default constructor

public Shape(){

this.shape = "unknown";

this.area = 0.0;

this.perimeter = 0.0;

}

//constructor with one parameter

public Shape(String shape){

this.setShape(shape);

this.area = 0.0;

this.perimeter = 0.0;

}

//accessors and mutators

public void setShape(String shape){

this.shape = shape;

}

public String getShape(){

return this.shape;

}

public double getPerimeter(){

return this.perimeter;

}

public double getArea(){

return this.area;

}

public void setPerimeter(Scanner scr){

if(this.getShape().equals("circle")){

System.out.println("Enter the radius of the circle");

double radius = scr.nextDouble();

this.perimeter = 2 * 3.142 * radius;

}

else if(this.getShape().equals("rectangle")){

System.out.println("Enter the width");

double width = scr.nextDouble();

System.out.println("Enter the height");

double height = scr.nextDouble();

this.perimeter = 2 * (width + height);

}

else if(this.getShape().equals("square")){

System.out.println("Enter the height or width");

double height = scr.nextDouble();

this.perimeter = 4 * height;

}

else if(this.getShape().equals("unknown")){

System.out.println("You must define a shape first before calculating perimeter");

this.perimeter = 0.0;

}

else {

System.out.println("You must define a shape first before calculating perimeter");

this.perimeter = 0.0;

}

public void setArea(Scanner scr){

if(this.getShape().equals("circle")){

System.out.println("Enter the radius of the circle");

double radius = scr.nextDouble();

this.area = 3.142 * radius * radius;

}

else if(this.getShape().equals("rectangle")){

System.out.println("Enter the width");

double width = scr.nextDouble();

System.out.println("Enter the height");

double height = scr.nextDouble();

this.area = width * height;

}

else if(this.getShape().equals("square")){

System.out.println("Enter the height or width");

double height = scr.nextDouble();

this.area = height * height;

}

else if(this.getShape().equals("unknown")){

System.out.println("You must define a shape first before calculating area");

this.area = 0.0;

}

else {

System.out.println("You must define a shape first before calculating area");

this.area = 0.0;

}

//Own methods

//1. Method to show the properties of a shape

public void showProperties(){

System.out.println();

System.out.println("The properties of the shape are");

System.out.println("Shape : " + this.getShape());

System.out.println("Perimeter : " + this.getPerimeter());

System.out.println("Area : " + this.getArea());

}

//2. Method to find and show the difference between the area and perimeter of a shape

public void getDifference(){

double diff = this.getArea() - this.getPerimeter();

System.out.println();

System.out.println("The difference is " + diff);

}

========= ShapeTest.java ===========

import java.util.Scanner;

public class ShapeTest {

public static void main(String [] args){

Scanner scanner = new Scanner(System.in);

// create an unknown shape

Shape shape_unknown = new Shape();

//get the shape

System.out.println("The shape is " + shape_unknown.getShape());

//set the area

shape_unknown.setArea(scanner);

//get the area

System.out.println("The area is " + shape_unknown.getArea());

//set the perimeter

shape_unknown.setPerimeter(scanner);

//get the perimeter

System.out.println("The perimeter is " + shape_unknown.getPerimeter());

// create another shape - circle

Shape shape_circle = new Shape("circle");

//set the area

shape_circle.setArea(scanner);

//get the area

System.out.println("The area is " + shape_circle.getArea());

//set the perimeter

shape_circle.setPerimeter(scanner);

//get the area

System.out.println("The perimeter is " + shape_circle.getArea());

//get the properties

shape_circle.showProperties();

//get the difference between area and perimeter

shape_circle.getDifference();

}

<h2>Sample output:</h2>

The shape is unknown

You must define a shape first before calculating area

The area is 0.0

You must define a shape first before calculating perimeter

The perimeter is 0.0

Enter the radius of the circle

>> 12

The area is 452.448

Enter the radius of the circle

>> 12

The perimeter is 452.448

The properties of the shape are

Shape : circle

Perimeter : 75.408

Area : 452.448

The difference is 377.03999999999996

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.

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