For
|a|<b
assume
-b<a<b
so
add 5 to both side
|-2-8x|<66
assume
-66<-2-8x<66
add 2 to both sides
-64<-8x<68
divide everyboy by -8, don't forget to flip sign
8>x>-8.5
-8.5<x<8
the solution is all numbers between -8.5 and 8, not including -8.5 and 8
in interval notation: (-8.5,8)
or
S={x|-8.5<x<8}
Answer:
400 m^2.
Step-by-step explanation:
The largest area is obtained where the enclosure is a square.
I think that's the right answer because a square is a special form of a rectangle.
So the square would be 20 * 20 = 400 m^2.
Proof:
Let the sides of the rectangle be x and y m long
The area A = xy.
Also the perimeter 2x + 2y = 80
x + y = 40
y = 40 - x.
So substituting for y in A = xy:-
A = x(40 - x)
A = 40x - x^2
For maximum value of A we find the derivative and equate it to 0:
derivative A' = 40 - 2x = 0
2x = 40
x = 20.
So y = 40 - x
= 40 - 20
=20
x and y are the same value so x = y.
Therefore for maximum area the rectangle is a square.
SSS I’m pretty sure . I’m doing the same thing in math rn
Answer:
x=12
Step-by-step explanation:
The right side is a right triangle
The base is 1/2 of the bottom or 5
The height is x and the hypotenuse is 13
We can use the Pythagorean theorem
a^2 +b^2 = c^2
5^2 +x^2=13^2
25+x^2 = 169
Subtract 25 from each side
25-25+x^2 = 169-26
x^2 =144
Take the square root of each side
sqrt(x^2) = sqrt(144)
x= 12
