Answer:
very easy A graph shows the horizontal axis numbered 2 to 8 and the vertical axis numbered 10 to 50. A line increases from 0 to 4 then decreases from 4 to 9.
Which type of function best models the data shown on the scatterplot?
Step-by-step explanation:
That is when h=0
so assuming yo meant
h(t)=-16t²+24t+16
solve for t such that h(t)=0
because when height=0, the gymnast hits the ground
so
0=-16t²+24t+16
using math (imma complete the square
0=-16(t²-3/2t)+16
0=-16(t²-3/2t+9/16-9/16)+16
0=-16((t-3/4)²-9/16)+16
0=-16(t-3/4)²+9+16
0=-16(t-3/4)²+25
-25=-16(t-3/4)²
25/16=(t-3/4)²
sqrt both sides
+/-5/4=t-3/4
3/4+/-5/4=t
if we do plus (because minus would give us negative height)
8/4=t
2=t
it takes 2 seconds
Answer:The function is nonlinear
Step-by-step explanation:
(-2/3, 2)
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Answer:
Two different transformations happen. Rotation/Reflection and translation (I say rotation/reflection because they can both put the parabola where it is after being transformed)
(Rotation- 180 degrees)
(Reflection across its it's starting point)
Translation- pushed up 4 points from negative 4 to 0 on the y-axis
When you put the parent function into a graph it is positive so the u is opening upward and starts at -4. Both sides of the u go through the points (0,0)and (4,0).
But in the transformed function is negative so the u opens downward. The sides going through the points (0,-4) and (4,-4)
I hope this makes sense
