X(p-6) = z-8 => x = (z-8)/(p-6) if p≠6
Answer:
There’s only one way to get 12 when 2 dice are tossed, both have to equal 6. There are 6 ways tossing a single die can come out (1,2,3,4,5,6), so if you toss dice, the second die could have any one of six values with each of the numbers that could result from the first toss (e.g., 1 from die 1 and 1,2,3,4,5, or 6 from die 2). So, considering there are 6 ways to fill each of two slots, there are 6 x 6 = 36 possible outcomes of tossing two dice. Only one of them equals 12, so p(12 given 2 dice tossed) = 1/36 = 0.02777777777778.
Answer:
Independent
Step-by-step explanation:
Answer: A function is a rule that assigns each value of the independent variable to exactly one value of the dependent variable.
Answer:
maybe there's a typo, that dot usually represents the multiplication, and I got 5.52
Answer:
The minimum score required for admission is 21.9.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

A university plans to admit students whose scores are in the top 40%. What is the minimum score required for admission?
Top 40%, so at least 100-40 = 60th percentile. The 60th percentile is the value of X when Z has a pvalue of 0.6. So it is X when Z = 0.255. So




The minimum score required for admission is 21.9.