Answer:
The daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.
Step-by-step explanation:
Since to rent a car, a person is charged a daily rate and a fee for each kilometer driven, and when Chena rented a car for 6 days and drove 320 km, the charge was $ 286.00, while when she rented the same car for 10 days and drove 900 km, the charge was $ 605.00, to determine the daily rate and the fee for each kilometer driven the following calculation must be performed:
286 = 6 days and 320 km
320/6 = 53,333 km
286/6 = $ 47,666
Thus, the value of 1 day and 53,333 km is $ 47,666.
605 = 10 days and 900 km
900/10 = 90 km
605/10 = $ 60.5
Thus, the value of 1 day and 90 km is $ 60.5.
90 - 53,333 = 36,666
60.5 - 47.666 = 12.833
12,833 / 36,666 = value per kilometer traveled
0.35 = value per kilometer traveled
(286 - (0.35 x 320)) / 6 = X
(286/112) / 6 = X
174/6 = X
29 = X
(605 - (0.35 x 900)) / 10 = X
(605 - 315) / 10 = X
290/10 = X
29 = X
Therefore, the daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.
Step-by-step explanation:
2.3141414...
= 2 + 3/10 + 14/990
= 2 + 311/990
= 2291 / 990
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Answer:
the answer 402
Step-by-step explanation:
Answer: 1. a) discriminant
4. b) No. when < 0 it has no Real solutions
<u>Step-by-step explanation:</u>
All of the other answers are correct.
In the quadratic expression, the solutions are defined by the discriminant (b² - 4ac) as follows:
- Discriminant < 0: 2 complex solutions (no Real solutions)
- Discriminant = 0: 1 Real Solution
- Discriminant > 0: 2 Real solutions
