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melomori [17]
3 years ago
12

G 3.6 Dice rolls. If you roll a pair of fair dice, what is the probability of (a) getting a sum of 1

Mathematics
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

0

Step-by-step explanation:

In the roll of a pair of fair dice, The sample space is as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

If x,y represent  the  possible outcome of rolling the two die

Then the total number of possibilities for  the sample space = (x,y)

= (6 × 6) = 36

Now, the probability of getting a sum of 1 does not exist in the roll of a pair of  fair dice.

Therefore, Probability(1) = 0

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P = 9r +3q <br><br> Work out the value of P when r = 6 and q = -4<br><br> P =
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Find the volume of a cylinder with a radius of 2 and a length of 9
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3 years ago
The school that Joe goes to is selling tickets to a choral performance. On血e first day of ticket
ArbitrLikvidat [17]

Answer:

The price of one senior citizen ticket is $8, and the price of one child ticket is $11.

Step-by-step explanation:

You are looking for two things: the price of a senior citizen ticket and the price of a child ticket.

We need to write two equations using two variables.

Let s = price of 1 senior citizen ticket.

Let c = price of 1 child ticket.

First day of ticket sales:

6 senior citizen tickets, 8 child tickets, total sales of $136

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 8 tickets cost 8c.

The total sales is 6s + 8c.

The total sales is $136, so our first equation is

6s + 8c = 136

Now we do the same for the second day of ticket sales.

6 senior citizen tickets, 9 child tickets, total sales of $147.

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 9 tickets cost 9c.

The total sales is 6s + 9c.

The total sales is $147, so our second equation is

6s + 9c = 147

The system of equations is

6s + 8c = 136

6s + 9c = 147

Multiply both sides of the first equation by -1. Write the second equation below it. Then add the equations.

       -6s - 8c = -136

(+)     6s + 9c = 147

----------------------------

                  c =   11

c = 11, so the cost of a child ticket is $11.

Now substitute 11 for c in the first equation, and solve for s.

6s + 8c = 136

6s + 8(11) = 136

6s + 88 = 136

6s = 48

s = 8

The price of a senior citizen ticket is $8.

The price of a senior citizen ticket is $8, and the price of a child ticket is $11.

6 0
2 years ago
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