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aleksley [76]
3 years ago
6

Walter and Brian each have a CD collection. • The number of CDs in Walter's collection can be represented by x. • The number of

CDs in Brian's collection is 3 times the number in Walter's collection. • The total number of CDs in both collections is 144. What is x, the number of CDs in Walter's collection?
Mathematics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

Number of CDs in Walter's collection = x = 36

Step-by-step explanation:

x denotes number of CDs in Walter's collection.

Also, the number of CDs in Brian's collection is 3 times the number in Walter's collection.

Number of CDs in Brian's collection =3x

Total number of CDs in both Walter's collection and Brian's collection = 144

x+3x=144\\4x=144\\x=\frac{144}{4}\\ x=36

So,

Number of CDs in Walter's collection = x = 36

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Solve the linear programming problem.
larisa [96]

Answer:

1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64

2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21

Step-by-step explanation:

1. Maximize: P = 4x +4y

Subject to: 2x + y ≤ 20

x + 2y ≤ 16

x, y ≥ 0

Plot the constraints and the objective function Z, or P=4x+4y)

Push the objective function to the limit permitted by the feasible region to find the maximum.

Answer: Objective function is a maximum at (16,0),

              Z = 4x+4y = 4(16) + 4(0) = 64

2. Maximize P = 3x + 2y

Subject to x + y ≤ 8

2x + y ≤ 13

x ≥ 0, y ≥ 0

Plot the constraints and the objective function Z, or P=3x+2y.

Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.

Answer: Objective function is at a maximum at (5,3),

              Z = 3x+2y = 3(5)+2(3) = 21

7 0
3 years ago
Find the sum of: 72 − 104 + 5 and -32 + 4 - 10. What should be added to 32 + 32 + 3 to get 3 + 3 ? (1 mark) 3. Subtract the sum
Rzqust [24]

Answer:

a). -65

b). -61

c). -20ab + 3bc +3ac

Step-by-step explanation:

According To the Question,

a). the sum of 72 − 104 + 5 and -32 + 4 - 10 .

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b). What should be added to 32 + 32 + 3 to get 3 + 3 , Let X be Added .

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c). Subtract  the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc – ac.

  • Thus, [(ab + 2bc) + (3bc – ac)] - [( 12ab –10bc –18ac) + (9ab + 12bc + 14ac)]
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baherus [9]
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Answer:

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Step-by-step explanation:

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