Answer:
1.-12*(2r)^11 * (3s)
= -12*2048*3 r^11 s
= -73728 r^11 s
2.12C1 (2r)¹¹(-3s) = -36(2¹¹)r¹¹s = -73728r¹¹s
3.24 r - 36 s
The second term: -36 s
4.(2r-3s)^12
= (2r)^12 + 12C1 (2r)^11 (-3s)
= 2^12 r^12 + (12) 2^11 r^11 (-3) s
= 4096 r^12 - (12)(3)(2098) r^11 s
= 4096 r^12 - 73,728 r^11 s + .....
-73,728 r^11 s
Step-by-step explanation:
Yan lang po alam ko at nahirapan ako e solved yan hehe pero hope it helps
This is a cubic binomial.
Tan⁴x - sec⁴x = 1 - 2sec²x
tan²x = sec²x - 1
tan⁴x - sec⁴x = 1 - 2sec²x
(tan²x)² - sec⁴x = 1 - 2sec²x
(sec²x - 1)² - sec⁴x = 1 - 2sec²x
(sec²x)² - 2 * sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x - 2 sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x can be cancelled:
- 2 sec²x + 1 = 1 - 2sec²x
1 - 2sec²x = 1 - 2sec²x
Answer:
C
Step-by-step explanation: