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Nimfa-mama [501]

3 years ago

15

The chemical element einsteinium-253 naturally loses its mass over time. A sample of an einsteinium-253 had an initial mass of 5

40 g when we measured it. The relationship the elapsed time T in months and the mass m(t) in grams left in the sample is modeled by the following function m(t)=540•(1/8)^t/2.05 complete the following sentence about the rate of change in the mass of the sample

1 answer:

qaws [65]3 years ago

8 0

Answer:

70

Step-by-step explanation:

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Find the slope of the line passi g through the points (-4, -5) and (6, -5).

Mamont248 [21]

Answer:

slope = 0

Step-by-step explanation:

slope = (y2 -y1) / (x2 - x1) = (- 5 -(-5)) / ((6 -(-4)) = (-5+5)/10 = 0/10 = 0

Horizontal line.

3 0

3 years ago

A large cable company reports the following:

Step2247 [10]

Answer:

$P(Cable\ TV\ only) = 50\%$

$P(Internet\ |\ cable\ TV) = 31.25\%$

$P(exactly\ 2\ services) = 23\%$

$P(Internet\ and\ cable\ TV \only) = 23\%$

Step-by-step explanation:

Given

$Cable\ TV = 80\%$

$Internet = 44\%$

$Telephone = 29\%$

$Cable\ TV\ and\ Internet = 25\%$

$Cable\ TV\ and\ Telephone = 20\%$

$Internet\ and\ Telephone = 23\%$

$All\ Services = 15\%$

Solving (a): A) P(cable TV only).

First, we calculate n(cable TV only)

This is calculated as:

$n(cable\ TV\ only) = (Cable\ TV) - (Cable\ TV\ and\ Internet) - (Cable\ TV\ and\ Telephone) + (All\ Services)$

$n(cable\ TV\ only) = 80\% - 25\% - 20\% + 15\%$

$n(cable\ TV\ only) = 50\%$

The probability is:

$P(Cable\ TV\ only) = \frac{n(Cable\ TV\ only)}{100\%}$

$P(Cable\ TV\ only) = \frac{50\%}{100\%}$

$P(Cable\ TV\ only) = 50\%$

Solving (b): P(Internet | cable TV).

This is calculated as:

$P(Internet\ |\ cable\ TV) = \frac{Cable\ TV\ and\ Internet}{Cable\ TV}$

$P(Internet\ |\ cable\ TV) = \frac{25\%}{80\%}$

$P(Internet\ |\ cable\ TV) = \frac{25}{80}$

$P(Internet\ |\ cable\ TV) = 31.25\%$

Solving (c): P(exactly 2 services).

This is calculated as:

$P(exactly\ 2\ services) = (Cable\ TV\ and\ Internet - All) + (Cable\ TV\ and\ Telephone - All) + (Internet\ and\ Telephone - All)$

$P(exactly\ 2\ services) = (25\% - 15\%) + (20\% - 15\%) + (23\%-15\%)$

$P(exactly\ 2\ services) = (10\%) + (5\%) + (8\%)$

$P(exactly\ 2\ services) = 23\%$

Solving (d): P(Internet and cable TV only).

This is calculated as:

$P(Internet\ and\ cable\ TV \only) = \frac{(Internet\ and\ cable\ TV \only)}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{1}$

$P(Internet\ and\ cable\ TV \only) = 23\%$

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lozanna [386]

Answer:

(0,1)

Step-by-step explanation:

To find when f(x)=g(x), then look for a value that is the same for both functions in the table. 1 occurs twice for the same x value. This is when they are equal. The solution is (0,1).

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Functions f(x) and g(x) are defined below.

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Which equation describes relationship between X and Y in the table?

MArishka [77]

Answer: the answer is a

Step-by-step explanation:

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