A.
For this case, let us set the variables:
s = 0 (final destination on the ground)
t = unknown
vo = 0
so = 8000 ft
Using the equation, we calculate for t:
0 = -16 t^2 + 0t + 8000
t = 22.36 s
B.
For this case:
s = unknown
t = 22.36 s
vo = 600 miles/hr = 880 ft/s
so = 0
Using the equation, we calculate for s:
s = -16*(22.36)^2 + 880*22.36 + 0
s = 11, 677.29 ft = 2.21 miles
Answer:
The UCL is 
The LCL is 
Step-by-step explanation:
From the question we are told that
The quantity of each sample is n = 30
The average of defective products is 
Now the upper control limit [UCL] is mathematically represented as
substituting values
The upper control limit (LCL) is mathematically represented as
substituting values
Hey there!
9 + 91 = 100
so x = 9
Hope this helps
Have a great day (:
Answer:
-3=1/v -7
-3+7= 1/v
4=1/v
v=1/4
In (-x)² you’re taking the value of x in the parentheses and then multiplying by the power of two while in just -x ² the power sign in directly on the number not on the parentheses. You will get the same answer both times for example x=10 (10)² or 10² both equal 100.
