Answer:
![r=\sqrt[3]{\frac{3V}{4\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D)
Step-by-step explanation:
We need to isolate 'r'
To isolate 'r' , first multiply by 3 on both sides
divide by 4pi on both sides
Take cube root on both sides
![\sqrt[3]{\frac{3V}{4\pi}}= r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D%3D%20r)
Select Is a Function or Is not a Function to correctly classify each relation.
<span><span>Title Is a Function Is not a Function</span><span><span><span><span>{<span><span>(<span>3, 7</span>)</span>,<span>(<span>3, 6</span>)</span>,<span>(<span>5, 4</span>)</span>,<span>(<span>4, 7</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>1, 5</span>)</span>,<span>(<span>3, 5</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>6, 4</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>2, 3</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>5, 8</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>0, 4</span>)</span>,<span>(<span>3, 2</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>6, 5</span>)</span></span>}</span></span>
</span></span></span>
Combine like terms. 6y-5y is 1y, which simplifies to y. the equation is y-3=15. y=18 is the answer because you add 3 to 15
You would add 5 and 1.2 which gives you 6.2 then you add negative 3.6 which then gives you 3.6.
