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Anon25 [30]
3 years ago
8

What is the first inverse operation needed to solve for p? 2p - 254= 900

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

inverse operation add (254 to other side)

2p - 254 = 900

     +254 = + 254

then divide

2p = 1154

/2  = /2

p  =  577

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Multiply (a + b + c ) (a + b + c)
saveliy_v [14]

Answer:

a squared plus b squared plus c squared.

Step-by-step explanation:

3 0
3 years ago
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What does volume measure?
Vinil7 [7]

Answer: d - the amount of space occupied by an object (its capacity)

Explanation:

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4 0
2 years ago
If x varies inversely as y, and x=6 when y=72, find x when y=36
Hoochie [10]

Answer:

12

Step-by-step explanation:

x = k/y           Multiply each side by y

k = xy            Insert values

  = 6 × 72

  = 432

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  = 432/36

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7 0
4 years ago
A container holds 4 gallons of lemonade. A large lemonade contains 16 ounces. How many large lemonades could the restaurant cell
Shalnov [3]

Given:

A container holds 4 gallons of lemonade.

A large lemonade contains 16 ounces.

To find:

The number of large lemonades that the restaurant can cell before they ran out of lemonade.

Solution:

We know that,

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4 gallon = 512 ounces

So, a container holds 512 ounces of lemonade.

A large lemonade contains 16 ounces. So,

\text{Number of large lemonades}=\dfrac{\text{Total lemonade in container}}{\text{Lemonade in a large container}}

\text{Number of large lemonades}=\dfrac{512}{16}

\text{Number of large lemonades}=32

Therefore, the required number of lemonades is 32.

3 0
3 years ago
The task I need explaining is: how to show that an estimate of the mean time spent on homework is 64.8 minutes. Thanks!
xenn [34]
It's just an estimate.  There's no telling how close it is.

To estimate using just the information in the table,
ASSUME that the average of all the students in each
slot is the average time of that slot.

I know that's confusing.  I can't think of a better way to say it,
so here are two examples of what I mean.  Look at the table:

-- 6 students said that they spent between 0 and 30 minutes.
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-- 21 students said that they spent between 60 and 90 minutes.
   ASSUME that those 21 students averaged 75 minutes each.

So, when you add up the times for all 50 students, you'll have

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When you total up all those times, divide it by 50 to estimate
the average per student.  

Remember ... it's only an estimate.
If the first group had 1 student that spent 2 minutes, and
the other 5 of them spent 29 minutes, then it won't work.
But you'll never know.
5 0
3 years ago
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