Answer:
The solution to the system of equation would be the two order pairs (2,10) and (-1,16)
Explanation:
The solution means the value of x that satisfies both equations.
Therefore, we will equate the two equations given and solve for x.
The first is: y = x^2 - 3x + 12
The second is : y = -2x + 14
Equate both and solve for x as follows:
x^2 - 3x + 12 = -2x + 14
x^2 - 3x + 2x + 12 - 14 = 0
x^2 - x - 2 = 0
(x-2)(x+1) = 0
either x = 2 and y = (2)^2 - 3(2) + 12 = -2(2) + 14 = 10
or x = -1 and y = (-1)^2 - 3(-1) + 12 = -2(-1) + 14 = 16
Therefore, the solution to the system of equation would be the two order pairs (2,10) and (-1,16)
Hope this helps :)
Answer:Option C:
64 \ cm^2 is the area of the composite figure
It is given that the composite figure is divided into two congruent trapezoids.
The measurements of both the trapezoids are
b_1=10 \ cm
b_2=6 \ cm and
h=4 \ cm
Area of the trapezoid = \frac{1}{2} (b_1+b_2)h
Substituting the values, we get,
A=\frac{1}{2} (10+6)4
A=\frac{1}{2} (16)4
A=32 \ cm^2
Thus, the area of one trapezoid is $32 \ {cm}^{2}$
The area of the composite figure can be determined by adding the area of the two trapezoids.
Thus, we have,
Area of the composite figure = Area of the trapezoid + Area of the trapezoid.
Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2
Thus, the area of the composite figure is 64 \ cm^2
Step-by-step explanation:
Explain more please if you can
31-21=15
Answer: 15m
Answer check: 36+15=51✅
