(2,12). Moving left to right is the x, moving up and down is the y.
To subtract fractions, let's put a generic example.
Be the fractions
(a / b) - (c / d)
With a, b, c and d other than zero.
The subtraction of fractions is given by:
(a / b) - (c / d) = ((a * d) - (c * b)) / (b * d).
If the fractions have the same denominator then the subtraction is
(a / b) - (c / b) = (a-c) / (b)
answer
(a / b) - (c / d) = ((a * d) - (c * b)) / (b * d)
(a / b) - (c / b) = (a-c) / (b)
≈ 6 (in simplest form)
Answer is <em>5 S.R. 6 </em>
Answer:
area after 8 years is 2156km²
Step-by-step explanation:
Area of forest=4900 km²
decrease in area in 1 year=4900km² × 7%
decrease in area in 1 year= 343km²
decrease area in 8 years=343km² × 8
=2744km²
Remaining area= (4900-2744)km²
=2156km²
Note:If you have any question about it please ask.
Answer:
It would take 75.8 minutes for the element to decay to 2 grams.
Step-by-step explanation:
The number of grams of element x, after t minutes, is given by the following equation:

In which X(0) is the initial amount and r is the decay rate.
There are 160 grams of Element X
This means that X(0) = 160.
So


Half life of 12 minutes.
This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So



![\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B%281%20-%20r%29%5E%7B12%7D%7D%20%3D%20%5Csqrt%5B12%5D%7B0.5%7D)

So


How long would it take for the element to decay to 2 grams?
This is t for which X(t) = 2. So







It would take 75.8 minutes for the element to decay to 2 grams.