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aleksklad [387]
3 years ago
13

PLEASE AWNSER ASAP will mark BRAINLEST!!!What are the coordinates of the image of point B, after the segment has been dilated by

a scale factor of 3 with a center of dilation at the origin? On a coordinate plane, line segment A B has points (negative 6, 8) and (negative 3, 3). (–9, 9) (9, –9) (–1, 1) (1, –1)
Mathematics
2 answers:
Dovator [93]3 years ago
8 0

Answer:

  (-9, 9)

Step-by-step explanation:

Each coordinate is multiplied by the scale factor.

  B' = 3B

  B' = 3(-3, 3)

  B' = (-9, 9)

Tcecarenko [31]3 years ago
8 0

Answer:

B'(-9,9)

Step-by-step explanation:

Given:

A(-6,8)

B(-3,3)

Dilation: factor = 3,

centre of dilation = (0,0)

Solution:

Image of B

B' = 3(-3,3) = (-9,9)

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A certain forest covers an area of 4900 km². Suppose that each year this area decreases by 7%. What will the area be after 8 yea
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3 0
3 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 160
Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

X(t) = X(0)(1-r)^{t}

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

So

X(t) = X(0)(1-r)^{t}

X(t) = 160(1-r)^{t}

Half life of 12 minutes.

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X(t) = 160(1-r)^{t}

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So

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X(t) = 160(0.9438)^{t}

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

X(t) = 160(0.9438)^{t}

2 = 160(0.9438)^{t}

(0.9438)^{t} = \frac{2}{160}

\log{(0.9438)^{t}} = \log{\frac{2}{160}}

t\log{0.9438} = \log{\frac{2}{160}}

t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}

t = 75.8

It would take 75.8 minutes for the element to decay to 2 grams.

6 0
3 years ago
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