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Eduardwww [97]
3 years ago
12

CAN U PLEASE HELP AS FAST AS POSSIBLE

Mathematics
2 answers:
patriot [66]3 years ago
8 0
The best answer would be C. 5/14 :)
kondaur [170]3 years ago
5 0

Answer:

5/14 is the answer I believe

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Re-post: Hello, can anyone do my school work for me or at least help me? I'm in 6th grade in FLVS I need to finish by July 15 i
harkovskaia [24]

Answer:

Do you have the math exercices? I am sorry but I can just help in the subjects concerning math. It is been some time since I studied biology and other high-school subjects.

3 0
3 years ago
marking brainlist. please help What is the first inverse operation for the following problem? 3x+4=12
Strike441 [17]

Answer:

3x + 4 = 12 :- x = 8 / 3

Step-by-step explanation:

3x + 4 = 12

Move all terms not containing x to the right side of the equation.

Subtract 4 from both sides of the equation.

3x = 12 - 4

Subtract 4 from 12.

3x = 8

Divide each term by 3 and simplify.

Divide each term in 3x = 8 by 3.

3x / 3 = 8 / 3

Cancel the common factor of 3.

Divide x by 1.

x = 8 / 3

The result can be shown in multiple forms.

Exact Form:

x = 8 / 3

Decimal Form:

x = 2.6

Mixed Number Form:

x = 2 2/3

3 0
3 years ago
A certain experimental mathematics program was tried out in 2 classes in each of 32 elementary schools and involved 37 teachers.
zheka24 [161]

Answer:

A) 0 and 13

Step-by-step explanation:

64 - 37 = 27

27/2 = 13.5

13 teachers can teach 3 classes at max

6 0
3 years ago
Which expression is a PRODUCT?
Lesechka [4]
The answer is A thanks for asking
8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
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