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GuDViN [60]
3 years ago
12

Find the slope of the line that passes through the points (5,3) and (6,9)

Mathematics
1 answer:
san4es73 [151]3 years ago
8 0

Answer:

6

Step-by-step explanation:

We can find the slope from

m = (y2-y1)/(x2-x1)

   = (9-3)/(6-5)

   = 6/1

   =6

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2/5 of a Number is what percentage of that number<br><br> HELP
Nata [24]

Answer: 40%

Step-by-step explanation: 100 ÷ 5 = 20 so 20 × 2 = 40

7 0
3 years ago
Prove the following identity true. Show work.
yulyashka [42]

Answer:

The  Pythagorean identity states that

\sin^2 t + \cos^2 t = 1

Using that we can rewrite the left denominator as:

1 - \sin^2 t

Which can be factored as

(1 - \sin t)(1+ \sin t)

The numerator we can expand as:

(1 - \sin t)(1 - \sin t)

On the right hand side, let's multply numerator and denominator with (1 - sin t):

The total formula then becomes:

\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}

There you go... left and right are equal.

3 0
3 years ago
Read 2 more answers
Please answer this correctly
Lynna [10]

Answer:

75%

Step-by-step explanation:

There is 1 whisker and quartiles 1-3 so:

25%+25%+25%=75%

6 0
3 years ago
Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)
iris [78.8K]

The point-slope form:

y-y_1=m(x-x_1)

We have the point (1, 6) and the slope m = 7/3. Substitute:

y-6=\dfrac{7}{3}(x-1)      <em>use distributive property</em>

y-6=\dfrac{7}{3}x-\dfrac{7}{3}          <em>add 6 to both sides</em>

y=\dfrac{7}{3}x+\dfrac{11}{3}        <em>multiply both sides by 3</em>

3y=7x+11           <em>subtract 7x from both sides</em>

-7x+3y=11         <em>change the signs</em>

7x-3y=-11

Answer:

point-slope form: y-6=\dfrac{7}{3}(x-1)

slope-intercept form: y=\dfrac{7}{3}x+\dfrac{11}{3}

standard form: 7x-3y=-11

5 0
3 years ago
Solve the equation for a.<br><br> K=4a+9ab
ale4655 [162]

Answer:

a= k/4+9b

Step-by-step explanation:

hope this helps, if not let me know!

3 0
3 years ago
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