Answer:Solve for h V=1/3pir^2h. V=13πr2h V = 1 3 π r 2 h. Since h h is on the right side of the equation, switch the sides so it is on the left side of the equation. 13⋅(πr2h)=V 1 3 ⋅ ( π r 2 h ) = V. Simplify the left side.
Step-by-step explanation:
Solve for h V=1/3pir^2h. V=13πr2h V = 1 3 π r 2 h. Since h h is on the right side of the equation, switch the sides so it is on the left side of the equation. 13⋅(πr2h)=V 1 3 ⋅ ( π r 2 h ) = V. Simplify the left side.
PEMDAS = Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.
So multiplication first, 56*2= 112
Division second, 5/5=1
Subtraction last, so 112 - 1 = 111
111 is the answer.
1) First one is a line f(x)=2x+1. It has y-int. (0,1), and second point, for example, (1,3)
2 points for line (0,1) and (1,3)2) Second one is a parabola g(x)=x²+2x-8.
In the vertex form it looks like
g(x) =x²+2x+1-1-8=(x+1)²-9
g(x)=(x+1)²-9 - parabola in the vertex form. Vertex is (-1,-9)Another point of the parabola can be found from the equation g(x)=x²+2x-8.
It is y-int. x=0, g(0)=-8, so
point on the parabola is (0,-8)For parabola Vertex (-1,-9) and point (0,-8)3) Solutions are (-3,-5) and (3,7).
Answer:
ok
Step-by-step explanation:
6+3w (don't mind this it has to be 20 characters long)