$\text{Let the coordinates of AB are }A(-5,-1), \text{ and }B(-2, -6)\\
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\text{let the coordinate of th point C be (x, y), such that}\\
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AC:CB=3:7\\
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\text{By the section formula, we know that if P(x,y) lies on a line segment AB}\\
\text{where, }A(x_1,y_1), \ B(x_2,y_2)\text{ and satisfy the ratio, }AP:PB=m:n, \text{ then}$

$P=\left ( \frac{mx_2+nx_1}{m+n}, \ \frac{my_2+ny_1}{m+n} \right ).\\
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\text{So using this formula, we get for the given problem}\\
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C=\left ( \frac{3(-2)+7(-5)}{3+7}, \ \frac{3(-6)+7(-1)}{3+7} \right )\\
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\Rightarrow C=\left ( \frac{-6-35}{10}, \ \frac{-18-7}{10} \right )\\
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\Rightarrow C=\left ( \frac{-41}{10}, \ \frac{-25}{10} \right )\\
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\Rightarrow C=\left ( -4.1, \ -2.5 \right )$

Coordinates of the point C is: (-4.1, -2.5)

5 0

3 years ago

Test time limit need answer quickly!

Rus_ich [418]

Answer:

its b!!! gimmie brainliest

3 0

2 years ago

Last one for the night but yeah

Jobisdone [24]

Answer: RQS= 90, QRS= 43, QSR= 47

Solving Steps:
180-90=90 (all the angles combined equal 180)
9x-2+10x-3=90
19x-5=90
19x=90+5
19x=95
x=5

9(5)-2= 43
10(5)-3= 47

4 0

3 years ago