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cupoosta [38]
2 years ago
5

Maria worked 5.1 hours on Monday and 7.35 hours on Tuesday. She gets paid $9.20 an hour. How much, in dollars, did Maria earn th

is week
Mathematics
2 answers:
Yanka [14]2 years ago
8 0

105.34 and you would first add the hours together so 5.1 + 7.35= 11.45 then you would multiple $9.20 X 11.45= 105.34

mixas84 [53]2 years ago
6 0

Answer:

$114.54

Step-by-step explanation:

In order to answer this question, we are going to have to do some multiplication :)

First, we will find out how much Maria got paid on Monday. In order to find this, we must multiply 5.1 hours by $9.20, so

5.1 * 9.20 = 46.92

We will be using this number a little later. Next, we have to find out how much Maria got paid on Tuesday, so we have to multiply 7.35 hours by $9.20, so

7.35 * 9.20 = 67.62

Now, we will combine the numbers:

67.62 + 46.92 = 114.54

Therefore, Maria earned $114.54 this week

Hope this helps :)

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Suppose the lifetime of a cell phone battery is normally distributed with a mean of 36 months and a standard deviation of 2 mont
solong [7]

Answer:

They should guarantee the lifetime of their batteries for 32 months.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 36 months and a standard deviation of 2 months.

This means that \mu = 36, \sigma = 2

If the company wants to replace no more than 2% of all batteries, for how many months should they guarantee the lifetime of their batteries?

The guarantee should be the 2th percentile of lengths, which is X when Z has a pvalue of 0.02. So X when Z = -2.054.

Z = \frac{X - \mu}{\sigma}

-2.054 = \frac{X - 36}{2}

X - 36 = -2.054*2

X = 31.89

Rounding to the closest month, 32.

They should guarantee the lifetime of their batteries for 32 months.

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