Answer:
I guess you want to find the relative frequencies:
In total, we have 396,651 children
in sample 1, we have 198,747 children, and of those, only 37 developed the disease.
This means that the vaccine is not effective in:
p = 37/198,747 = 0.00019
For the placebo, we have a sample of 197,904 children in total, and 111 of them developed the disease, then we have a probability of the placebo not being effective is:
p = 111/197,904 = 0.00056
So we can see that the difference is significant, meaning that the placebo is not effective in more than twice the cases where the vaccine is not effective.
F(x)= 5(-x^3)-3+2
f(x)=5(-x^3)-1
Answer:
-3.66
Step-by-step explanation:
6x-3=-25
6x=-22
X=-3.66
<h3>
Answer: D. x = 4</h3>
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Explanation:
First compute f(2)
f(x) = 3x-1
f(2) = 3(2) - 1 ... replace every x with 2; use PEMDAS to simplify
f(2) = 6 - 1
f(2) = 5
When we say g(x) = f(2), we really mean g(x) = 5
g(x) = 2x-3
2x-3 = g(x)
2x-3 = 5 .... plug in g(x) = 5
2x-3+3 = 5+3 ... add 3 to both sides
2x = 8
2x/2 = 8/2 ... dividing both sides by 2
x = 4