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Lelu [443]
3 years ago
5

The temperature at the boiling point remained constant despite the continued addition of heat by the Bunsen burner. What was the

energy used for? Select one: Energy was not conserved under these conditions. The energy was used to form intermolecular bonds between the water molecules. The energy was released by the water as heat, which warmed up the surroundings. The energy was used to overcome the attractions between the water molecules.
Chemistry
1 answer:
aliina [53]3 years ago
5 0

Answer:

The energy was used to overcome the attractions between the water molecules.

Explanation:

At the boiling point, there is no further increase in temperature by the heat. Rather the additional heat energy is used in breaking down the bonds so as to lead to change in state - from liquid to gaseous state.

The correct option is;

The energy was used to overcome the attractions between the water molecules.

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6.201cm+7.4cm+0.68 cm+12.0cm
zimovet [89]
If you want the answer is centimeters is it going to be:
26.281 cm
If it make it easier for you to solve add 6.201 and 7.4 which will equal 13.601. Then add .68 to 13.601 which equals 14.281. Last add 12 to 14.281 which equals 26.281.

Hope this helps.

8 0
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What is the percent composition by mass of aluminum in Al2(SO4)3 (gram-formula mass = 342 grams/mole)?
Aliun [14]
The atomic mass of Aluminum is around 27 amu. There are two aluminum atoms, so it takes 54 amu. The gram-formula states that 1 mole of this compound has 342 grams. By definition, this means that the total amu of this compound is 342. Therefore, we divide 54 by 342 to get around 15.8 %. 

8 0
3 years ago
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The crystal size of an igneous rock is described as its _____.​
Mila [183]

Answer:

The crystal size of an igneous rock is described as its texture.

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(On the verge of tears)
zhenek [66]

Answer: The final molarity of a 20mL- 1.3M salt solution after it has been diluted with 100ml water is 0.22 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock solution = 1.3  M

V_1 = volume of stock solution = 20 ml  

M_1 = molarity of diluted solution = ?

V_1 = volume of  diluted solution = (20+100) ml = 120 ml

Putting in the values we get:

1.3\times 20=M_2\times 120

M_2=0.22M

Therefore  the final molarity of a 20mL- 1.3M salt solution after it has been diluted with 100ml water is 0.22 M

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drek231 [11]

Answer:

Synthesis :)

Explanation:

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