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4 years ago

According to the image, identify the number of neutrons in the most common isotope of aluminum. A) 13 B) 14 C) 26 D) 27

Chemistry

2 answers:

MrRa [10]4 years ago

5 0

Hi There!

Question - According to the image, identify the number of neutrons in the most common isotope of aluminum.

Answer - 14

Why - The reason I say it's 14 is because you don't need a picture to solve this question, the question is simple where its just asking for the amount of neutrons in common isotope of aluminum.

Hope This Helps :)

barxatty [35]4 years ago

4 0

the correct answer is 14

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What is the pH of a buffer solution upon mixing 15.0 mL of 0.40 M HCl and 20.0 mL of 0.50 M NH? Kb (NH3) = 1.8 x 10 E. 7.00 A. 9

vladimir2022 [97]

Answer: The pH of resulting solution is 9.08

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ ........(1)

For HCl:

Molarity of HCl = 0.40 M

Volume of solution = 15.0 mL

Putting values in equation 1, we get:

$0.40M=\frac{\text{Moles of HCl}\times 1000}{15.0mL}\\\\\text{Moles of HCl}=0.006mol$

For ammonia:

Molarity of ammonia = 0.50 M

Volume of solution = 20.0 mL

Putting values in equation 1, we get:

$0.50M=\frac{\text{Moles of ammonia}\times 1000}{20.0mL}\\\\\text{Moles of ammonia}=0.01mol$

The chemical reaction for hydrochloric acid and ammonia follows the equation:

$HCl+NH_3\rightarrow NH_4Cl$

Initial: 0.006 0.01

Final: - 0.004 0.006

Volume of solution = 15.0 + 20.0 = 35.0 mL = 0.035 L (Conversion factor: 1 L = 1000 mL)

To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

$pOH=pK_b+\log(\frac{[salt]}{[base]})$

$pOH=pK_b+\log(\frac{[NH_4Cl]}{[NH_3]})$

We are given:

$pK_b$ = negative logarithm of base dissociation constant of ammonia = $-\log (1.8\times 10^{-5})=4.74$

$[NH_4Cl]=\frac{0.006}{0.035}$

$[NH_3]=\frac{0.004}{0.035}$

pOH = ?

Putting values in above equation, we get:

$pOH=4.74+\log(\frac{0.006/0.035}{0.004/0.035})\\\\pOH=4.92$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\pH=14-4.92=9.08$

Hence, the pH of the solution is 9.08

3 0

4 years ago

Ethers are almost always used as solvents for Grignard reactions, all of the reasons why they work so well are not fully underst

vfiekz [6]

Answer:

Ether is used as a solvent because it is aprotic and can solvate the magnesium ion.

Explanation:

Solubility in Water

Because ethers are polar, they are more soluble in water than alkanes of a similar molecular weight. The slight solubility of ethers in water results from hydrogen bonds between the hydrogen atoms of water molecules and the lone pair electrons of the oxygen atom of ether molecules.

Ethers as Solvents

Ethers such as diethyl ether dissolve a wide range of polar and nonpolar organic compounds. Nonpolar compounds are generally more soluble in diethyl ether than alcohols because ethers do not have a hydrogen bonding network that must be broken up to dissolve the solute. Because diethyl ether has a moderate dipole moment, polar substances dissolve readily in it.

Ethers are aprotic. Thus, basic substances, such as Grignard reagents, can be prepared in diethyl ether or tetrahydrofuran. These ethers solvate the magnesium ion, which is coordinated to the lone pair electrons of diethyl ether or THF. Figure attached, shows the solvation of a Grignard reagent with dietheyl ether.

The lone pair electrons of an ether also stabilize electron deficient species such as BF3 and borane (BH3). For example, the borane-THF complex is used in the hydroboration of alkenes (Section 1

5 0

4 years ago

How many moles of water are in 1.23x10¹8 water molecules? [ ? ]×10[?]

Sergio [31]

Answer:

2.04 x 10⁻⁶ moles H₂O

Explanation:

To find the moles H₂O, you need to multiply the given value by Avogadro's Number. This number is a ratio between molecules and moles, thus granting you the way to convert between both units. It is important to arrange the ratio in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (1.23 x 10¹⁸ molecules).

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

1.23 x 10¹⁸ molecules H₂O 1 mole
--------------------------------------- x ------------------------------------- =
6.022 x 10²³ molecules

= 2.04 x 10⁻⁶ moles H₂O

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2 years ago

How many moles of mercury are produced if 24.5 moles of mercury (II) oxide decompose?

aev [14]

Answer:

24.5 moles of mercury are produced

Explanation:

The descomposition of mercury(II) oxide, occurs as follows:

2HgO → 2Hg + O₂

Where 2 moles of HgO produce 2 moles of Hg

In other words, the ratio of descomposition of HgO/Hg is 2/2 = 1:1

That means, if 24.5 moles of mercury(II) oxide descompose:

<h3>24.5 moles of mercury are produced</h3>

4 0

3 years ago

I don't know how to get the volume and it is 10 point removed for it wrong so can someone help me

In-s [12.5K]

16.91

Add all the values for the volume added then divide by 3 because there are three values

7 0

3 years ago