The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.
<h3>
Could the graphed function have a degree 4?</h3>
For a polynomial of degree N, we have (N - 1) changes of curvature.
This means that a quadratic function (degree 2) has only one change (like in the graph).
Then for a cubic function (degree 3) there are two, and so on.
So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).
Then we can write:
y = a*x^4 + c*x^2 + d
That is a polynomial of degree 4, but if we choose x^2 = u
y = a*u^2 + c*u + d
So it is equivalent to a quadratic polynomial.
Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).
If you want to learn more about polynomials:
brainly.com/question/4142886
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Answer:
153/20
Step-by-step explanation:
I assume you're asking
So
=
Answer:
hi
Step-by-step explanation:
Answer:
31/40 of the trail
Step-by-step explanation:
he completed 9/10 of the trail (or 72/80 because 9*8 is 72)
He went back 1/8 of the trail (or 10/80 because 1*10 is 10)
72-10 is 62
he went 62/80, simplified is 31/40 of the trail
X^3+8
= x^3+2^3
<span>a^3 + b^3 = (a + b)(a^2 – ab + b^2)</span>
so
x^3+8
= x^3+2^3
= (x+2)(x^2-2x+2^2)
= (x+2)(x^2-2x+4)
