3 years ago

Need help with these two questions linear relations.

Mathematics

1 answer:

wel3 years ago

3 0

Answer:

b. y = -7x + 4

1. y = -7(-5)+ 4 = 35+4= 39

2. -24= -7x + 4

-28 = -7x

4 = x

3. y = -7(0)+4= 4

4. 0 = -7x+4

-4= -7x

4/7 = x

c. 3y - 5x = 15

1. 3y - 5(6)

3y-30=15

3y=45

y = 15

2. 3(-10)-5x=15

-30-5x=15

-5x = 45

x = -9

3. 3y-5(0)=15

3y=15

y=5

4. 3(0)-5x=15

0-5x=15

-5x=15

x=-3

Step-by-step explanation:

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The terms $-12x^2y$ and $4x^2y$ can be added to $3x^2y$ to result in a monomial.

Step-by-step explanation:

Given term is;

$3x^2y$

A monomial is an algebraic expression that consists of only one term.

So in the given expressions, we will add the terms which have same variables as given terms.

Given options are;

$3xy\\-12x^2y\\2x^2y^2\\7xy^2\\-10x^2\\4x^2y\\3x^3$

The terms $-12x^2y$ and $4x^2y$ can be added to $3x^2y$ to result in a monomial.

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