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Anna [14]
3 years ago
10

Need help with these two questions linear relations.

Mathematics
1 answer:
wel3 years ago
3 0

Answer:

b. y = -7x + 4

   1.    y = -7(-5)+ 4 = 35+4= 39

   2. -24= -7x + 4

    -28 = -7x

       4 = x

    3. y = -7(0)+4= 4

    4. 0 = -7x+4

        -4= -7x

         4/7 = x

c. 3y - 5x = 15

 1. 3y - 5(6)

    3y-30=15

    3y=45

      y = 15

   2. 3(-10)-5x=15

        -30-5x=15

         -5x = 45

            x = -9

    3. 3y-5(0)=15

        3y=15

         y=5

    4. 3(0)-5x=15

         0-5x=15

          -5x=15

           x=-3

Step-by-step explanation:

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suppose a parabola has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1). Write the eq
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Answer:

<h3>            f(x) = - 3(x + 8)² + 2</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k   - the vertex form of the quadratic function with vertex    (h, k)

the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8

the <u>maximum height of 2</u> means  k = 2

So:

f(x) = a(x - (-8))² + 2

f(x) = a(x + 8)² + 2   - the vertex form of the quadratic function with vertex   (-8, 2)

The parabola passing through the point (-7, -1) means that if x = -7 then        f(x) = -1

so:

    -1 = a(-7 + 8)² + 2

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      -3 = a

Threfore:

The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:

                                 <u>f(x) = -3(x + 8)² + 2</u>

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