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2 years ago

Please help now right noww

Mathematics

2 answers:

zzz [600]2 years ago

5 0

The opposite of 1 is -1.

The opposite of -1 is 1.

The opposite of -11 is 11.

The opposite of 30 is -30.

The opposite of 0 is 0.

The opposite of -16 is 16

The opposite of -(-8) is -8 because -(-8)=8 and the opposite of 8 is -8.

The opposite of 28 is -28.

The opposite of -(-65) is -65 because -(-65) = 8 and the opposite of 65 is 65

The opposite of 98 is -98.

The opposite of 100 is -100.

The opposite of -33 is 33.

Hope you found this answer helpful! Have a great day!

$GraceRosalia$

Likurg_2 [28]2 years ago

4 0

<h3>Answers:</h3>

6. -1

7. 1

8. 11

9. -30

10. 0

11. 16

12. -8

13. -28

14. -65

15. -98

16. -100

17. 33

<h3>Hope it helps..</h3>

Mark GraceRosalia Brainliest not me...I beg you to mark her Brainliest...Please please... infinity please

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which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x

pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case if the point $(2,80)$ satisfied the exponential function

<u>case A</u> $f(x)=4(x^{5})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=4(2^{5})=128$

$128\neq 80$

therefore

the exponential function $f(x)=4(x^{5})$ not passes through the point $(2,80)$

<u>case B</u> $f(x)=5(x^{4})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=5(2^{4})=80$

$80=80$

therefore

the exponential function $f(x)=5(x^{4})$ passes through the point $(2,80)$

<u>case C</u> $f(x)=4(5^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=4(5^{2})=100$

$100\neq 80$

therefore

the exponential function $f(x)=4(5^{x})$ not passes through the point $(2,80)$

<u>case D</u> $f(x)=5(4^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=5(4^{2})=80$

$80=80$

therefore

the exponential function $f(x)=5(4^{x})$ passes through the point $(2,80)$

therefore

<u>the answer is</u>

$f(x)=5(x^{4})$

$f(x)=5(4^{x})$

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