Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,

Consider right triangle ABE, by the Pythagorean theorem

Answer: 
Answer:
x = 67
Step-by-step explanation:
∠ CRQ = ∠ BQR = 113° ( Alternate angles )
∠ CRQ and ∠ CRS are adjacent angles and supplementary, that is
x + 113 = 180 ( subtract 113 from both sides )
x = 67
Answer:

Step-by-step explanation:

Answer:
It is 24%
Step-by-step explanation: