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Firlakuza [10]
3 years ago
5

Write 4 13/20 as a decimal

Mathematics
2 answers:
natali 33 [55]3 years ago
4 0
4.65 is the answer.

Hope I Helped!!
vredina [299]3 years ago
3 0
4 13/20 is 4.65 as a decimal.
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2(5x - 3) - 4 = x + 4 solve for x and show work
Katen [24]

Answer:

x= 14/9 = 1 5/9

Step-by-step explanation:

Use the distributive property to multiply 2 by 5x−3.

2(5x−3)−4=x+4

Subtract 4 from −6 to get −10.

10x−6−4=x+4

Subtract x from both sides

10x−10=x+4

Combine 10x and −x to get 9x.

10x−10−x=4

Add 10 to both sides.

9x−10=4

Divide both sides by 9.

x=  14/9

Please mark brainliest.

​  

 

4 0
3 years ago
Read 2 more answers
Comparing Relationships with Tables1. Decide whether each table could represent a proportional relationship.If the relationship
yan [13]

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

where

k is the constant of proportionality

Verify each table

table a

Let

x ----> distance

y ----> sound level

For each ordered pair calculate the value of k

k=y/x

so

(5,85) -----> k=85/5=17

(10,79) ----> k=79/10=7.9

the values of k are differents

that means

the table nor represent a proportional relationship

table b

let

x ----> volume

y ----> cost

k=y/x

(16,1.49) ----> k=1.49/16=0.093125

(20,1.59) ----> k=1.59/20=0.0795

the values of k are differents

that means

the table nor represent a proportional relationship

6 0
2 years ago
Point (2,3) is on a circle with the center (3,5). What is the radius of the circle?
ruslelena [56]
Can you add the picture to the question?
6 0
3 years ago
Read 2 more answers
Who invited math?? Please answer!!!!!
maksim [4K]

Answer:

Ancient Greeks

Beginning in the 6th century BC with the Pythagoreans, with Greek mathematics the Ancient Greeks began a systematic study of mathematics as a subject in its own right. Around 300 BC, Euclid introduced the axiomatic method still used in mathematics today, consisting of definition, axiom, theorem, and proof.

Step-by-step explanation:

6 0
3 years ago
Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1
kondaur [170]
f will be increasing on the intervals where f'(x)>0 and decreasing wherever f'(x). Local extrema occur when f'(x)=0 and the sign of f'(x) changes to either side of that point.

f'(x) is positive when x is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that f(x) is increasing on the intervals [-4, -2] and (2, 4].

f'(x) is negative when x is between some number between -2 and -1, up to some number less than 2. So f(x) is decreasing on the interval [-1, 1].

You then have two possible cases for extrema occurring. The sign of f'(x) changes for some x between -2 and -1, and again to either side of x=2.
4 0
3 years ago
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