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IgorLugansk [536]

2 years ago

15

Find the length of arc ABC. Express answer in terms of pi. PC=18in

2 answers:

lara31 [8.8K]2 years ago

7 0

Answer: $27\pi$

Step-by-step explanation:

In the given figure we have given a circle in with radius PC = 18 inches

Also, the central angle made by arc AC $90^{\circ}$ or $\dfrac{\pi}{2}$

Since the sum of angles at a point is $2\pi$

Then , the central angle made by arc AC :-

$\theta=2\pi-\dfrac{\pi}{2}=\dfrac{3\pi}{2}$

The formula to find the arc length is given by :-

$l=r\theta$

Then the length of arc ABC will be :-

$l=(18)(\dfrac{3\pi}{2})=27\pi$

Hence, the length of arc ABC = $27\pi$

Lapatulllka [165]2 years ago

3 0

The formula would be 2 * pi * (central angle)/360

Hence, 2 * 22/7 * 270/360 => 84.823 in.

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The proportion of students who own a cell phone on college campuses across the country has increased tremendously over the past

galina1969 [7]

Complete Question

The complete question is shown on the uploaded image

Answer:

1 ) The correct option B

2) The correct option is C

3) The correct option is C

4) The correct option is C

Step-by-step explanation:

From the question we are told that

The proportion that own a cell phone is $p = 0.90$

The sample size is n = 15

Generally the appropriate distribution for X is mathematically represented as

$X \ is \ B( n , p )$

So

$X \ is \ B( 15 , 0.90 )$

Generally the number students that own a cell phone in a simple random sample of 15 students is mathematically represented as

$\mu = n * p$

$\mu = 15 * 0.90$

$\mu = 13.5$

Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

$\sigma = \sqrt{ n * p * q }$

Where q is mathematically evaluated as

$q = 1- p$

$q = 1- 0.90$

$q = 0.10$

$\sigma = \sqrt{ 15 * 0.90 * 0.10 }$

$\sigma = 1.16$

Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

$P(X = 15) = \left 15} \atop {}} \right.C_{15} * p^{15} * q^{15 - 15}$

$P(X = 15) = \left 15} \atop {}} \right.C_{15} * (0.90)^{15} * (0.10 )^{15 - 15}$

From the combination calculator is $\left 15} \atop {}} \right.C_{15} = 1$

$P(X = 15) = 1 * 0.205891 * 1$

$P(X = 15) = 0.206$

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Umnica [9.8K]

Answer:

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Step-by-step explanation:

x+12=8

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Answer:

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Step-by-step explanation:

Let x represent the amount of lemons that were on the tree.

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