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pickupchik [31]

2 years ago

13

Find the gcf of 14,35,84

1 answer:

Paha777 [63]2 years ago

3 0

Answer:

7

Step-by-step explanation:

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Seven clowns hold 4 balloons each at the fair. Draw and label a tape diagram to show the total number of balloons the clowns hol

Inessa05 [86]

Answer:

7 times 4 which is 28 at each fair.

8 0

3 years ago

At noon (12:00 p.m.), three girls began jogging from the 0 -mile mark of a trail. Each girl jogged at her own steady pace. Drag

Dimas [21]

Cindy: 4mph
Taylin: 4m/30 min : 8 mph
Judy:5.5m/45min : 7mph

4 0

3 years ago

Read 2 more answers

Ryan says that the sum of any two numbers is rational. Which of the following is a counterexample?

GaryK [48]

Answer: 10 + 0.998987... = 10.998987

Step-by-step explanation:

I just took the test today and this was the answer.

5 0

2 years ago

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

<u>(b) Function c(n(h))</u>

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

<u>(d) Interpret (c)</u>

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

3 years ago

If the figure is rotated 270° counterclockwise about the origin, what is the length of segment N′P′?

kap26 [50]

Answer:

Option (2)

Step-by-step explanation:

Since, rotation of any figure is a rigid transformation, side lengths and measure of angles of the image polygon after rotation will remain same.

NP = N'P'

Coordinates of N → (5, 9)

Coordinates of P → (7, 9)

Formula of distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

By this formula length of NP = $\sqrt{(7-5)^2+(9-9)^2}$

= 2 units

Therefore, Option (2) will be the correct option.

7 0

2 years ago