Given x ^2 −3x+2=0
x ^2 −2x−1x+2=0
(Resolving the expression)
x(x−2)−1(x−2)=0 (Taking common factors)
(x−2)(x−1)=0 (Taking common factors)
∴x−2=0 or x−1=0 (Equating each factor to zero)
∴x=2 or x=1
∴2 and 1 are the roots of x ^2 −3x+2=0
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Answer:among us
Step-by-step explanation:
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Well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24
hence 24 is the correct answer....
u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....
as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.
I know this is pretty much confusing ....but still I tried my best....
if anything troubles u here feel free to ask me
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Answer:
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Step-by-step explanation:
13.9 sounds correct, try it
