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2 years ago

Solve the equation. Explain how you found your answer. 8y + 2y = 2y + 40

Mathematics

2 answers:

Jlenok [28]2 years ago

7 0

Answer:

y = 5

Step-by-step explanation:

Subtract 2y from either side. It'll cancel out both of them. Then the equation is 8y = 40.

Divide both sides by 8 and you get y=5

Pretty sure that's right. I have a dad who has a math degree so I think it would be right because he helps me every time.

Katyanochek1 [597]2 years ago

3 0

Step-by-step explanation:

As shown first you combine like terms then you subtract 2y from both sides to get 40 by it self then you divide 8 by 40 to get y by itself hope this helps this answer is 100% correct and i was glad to help please give brainliest!

$8y+2y=2y+40\\10y=2y+40\\ -2y -2y\\8y=40\\y=5$

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2 years ago

Aubrey used 4/7 liters of paint for a mural in her room and 2/10 liter for a wall in her bathroom. Determine a reasonable estima

NemiM [27]

Answer:

27/35 is the exact answer

7/10 is an estimate

Step-by-step explanation:

4/7+2/10

Simplify the fraction

4/7+1/5

The common denominator is 35

4/7*5/5 + 1/5 *7/7

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2 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

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