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wariber [46]
3 years ago
13

What is the solution to x 4 + 4x 3 ≤ 12x 2?

Mathematics
2 answers:
madam [21]3 years ago
8 0

Answer:

The answer is B

Step-by-step explanation:

[-6,2]

andriy [413]3 years ago
4 0

Answer:

-6,2

Step-by-step explanation:

im not sure what the answer is

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Need help as fast as possible will mark brainliest
MissTica

Answer:

Option C. is correct choice.

Step-by-step explanation:

20\pm 0.1\:^{\circ}\:C

Regards: Umer

6 0
3 years ago
Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7
sergeinik [125]
First we need to find where the 2 graphs intercept.

x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0 
2x(x - 2)

x = 0 , 2. are x coordinates  of the 2 intercepts.

6 0
3 years ago
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
3 years ago
A savings account with a current balance of $5,000 earns 2.75% annual interest, compounded continuously. To the nearest dollar,
Anna11 [10]
Use this formula. P=5000, r=0.0275, n=e, t=10

4 0
3 years ago
Read 2 more answers
Help please help help help
Artyom0805 [142]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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