All categories

2 years ago

The length of a rectangular garden is 4 less than twice the width find the perimeter and area of the garden

Mathematics

1 answer:

sergeinik [125]2 years ago

4 0

Answer:

Let w be the width. Then the length is 2w-4. So:

w(2w-4)=96

2w²-4w-96=0

w²-2w-48=0

(w-8)(w+6)=0

w=8 or -6

Throwing out the negative value for w, we get a width of 8 yds, and a length of 12 yds. ☺☺☺☺

You might be interested in

7^300 chia 7 dư bao nhiêu

Pepsi [2]

Answer:

dư 0... 7^300 chia 7 đc 7^299 mà

3 0

3 years ago

Ray CE is the angle bisector of ACD. Which statement about the figure must be true?

Viefleur [7K]

we know that

"Bisect" means to divide into two equal parts

If the ray CE is the angle bisector of ADC

then

$Angle(ACD)=Angle(ACE)+Angle(ECD)$

$Angle(ACE)=Angle(ECD)$

$Angle(ACD)=2Angle(ACE)$

$Angle(ACE)=\frac{1}{2} Angle(ACD)$

therefore

<u>the answer is the option</u>

$Angle(ACE)=\frac{1}{2} Angle(ACD)$

$Angle(ACE)=Angle(ECD)$

7 0

2 years ago

Read 2 more answers

A flower shop sells daffodils in bunches of 9 daffodils. The shop sells 27 daffodils. How many bunches of daffodils did the shop

amm1812

Answer:

its 3 brother

Step-by-step explanation:

you divide 27 by 9 and thats 3

6 0

3 years ago

Lydia buys 5 pounds of apples and 3 pounds of bananas for a total of $8.50. Ari buys 3 pounds of apples and 2 pounds of bananas

Anarel [89]

5x + 3y= 8.50
3x + 2y= 5.25

Lydia is the first equation. She bought 5 pounds of apples which is x and bought 3 pounds of bananas which is y. Basically, remember each banana and apple weighs a price per pound. We don't know the price so we just put an x. This is the same for the second equation

8 0

3 years ago

Read 2 more answers

For a binomial process, the probability of success is 40 percent and the number of trials is 5. Find the standard deviation.

Yakvenalex [24]

Answer:

$Sd(X) =\sqrt{1.2}=1.095$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=5, p=0.4)$