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3 years ago

Need help with question 3

Mathematics

1 answer:

Sloan [31]3 years ago

4 0

Answer:its lit and hibkrjngs fbsnrf

Step-by-step explanation:

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Anyone? Know how to do this?

ki77a [65]

Answer:

x = 4
length = 19 ft
width = 11 ft

Step-by-step explanation:

The area is given by the product of length and width.

A = LW

209 = (4x +3)(4x -5)

209 = 16x^2 -8x -15

224 = 16x^2 -8x

You could rearrange and use the quadratic formula at this point, but we elect to "complete the square".

14 = x^2 -(1/2)x

14 +1/16 = x^2 -1/2x +(1/4)^2 . . . . . add the square of half the x-coefficient

(x -0.25)^2 = 14.0625

x = 0.25 ± 3.75 . . . . . . take the square root; add 0.25

Only positive values of x are useful here, so we have

x = 4

Then the dimensions are ...

length = 4x +3 = 4(4) +3 = 19 . . . feet

width = 4x -5 = 16 -5 = 11 . . . feet

5 0

3 years ago

Number 4 only plzzz help asap its due tomorrow

____ [38]

B:
i=43 degrees
ii= 2 minutes
C:
10 degrees per minute
Sorry that's all I got

7 0

3 years ago

What do you need to know to describe the velocity of an object?--Three things total

spin [16.1K]

Answer:

Distance traveled, initial speed, and final sped.

Step-by-step explanation:

6 0

3 years ago

Which equation describes Which equation describes a line perpendicular to line R that passes through the point (3, -6)?

kompoz [17]

Answer:

Step-by-step explanation:

Big

4 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago