All categories

3 years ago

HELP PLEASEEEEEEEE!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

mariarad [96]3 years ago

7 0

Plus or minus 3. (The 1st answer)

x^2 means (-3*-3) which equals 9

x^2 means (3838) which also equals 9

6*9=54

Maksim231197 [3]3 years ago

7 0

First u would divide by 6 on both sides to get the x by itself and you would get x squared is equal to 9. Then u would take the sqaure root of both sides because u want to get rid of the squared and a sqaure root un do's that. After square rooting both sides you would get x = 3 because the square root of x squared is x and the square root of 9 is 3. so the answer is Plus or minus 3 or the first choice. Its also plus or minus because two negative 3's would give you nine and two positive 3's would give u 9.

You might be interested in

bonufazy [111]

A paln1 charges $0.35 per minute with no monthly fee (not sure )

4 0

3 years ago

About 543 out of every 1,000 people in United States owned a cell phone in 2003.In japan,the are was 68 for every 100 people.How

Softa [21]

Answer:

The greater percent of cell phone ownership in Japan than the U.S was <u>13.7%</u>.

Step-by-step explanation:

Given:

About 543 out of every 1,000 people in United States owned a cell phone in 2003.

In japan,the are was 68 for every 100 people.

Now, to find the greater percent of cell phone ownership in Japan than the U.S.

So, to get the percent of people owned cell phone in United States:

$\frac{543}{1000}\times 100$

$=0.543\times 100$

$=54.3\%.$

Now, to get the percent of people owned cell phone in Japan:

$\frac{68}{100} \times 100\\\\=0.68\times 100\\\\=68\%.$

So, to get the percent greater of cell phone ownership in Japan than the U.S we subtract the percent of people owned cell phone in United States from the percent of people owned cell phone in Japan:

$68\%-54.3\%\\\\=13.7\%.$

Therefore, the greater percent of cell phone ownership in Japan than the U.S was 13.7%.

5 0

3 years ago

Which expression is equivalent to 2(x^2-1) + 3x(x-4) (please show work)

Tema [17]

Answer:

5x^2-12x-2

Step-by-step explanation:

Use distributive property, then add like terms. See file below for steps.

4 0

3 years ago

What guides a researcher when deciding between using either linear, logistic, or Cox proportional hazards regression as an analy

castortr0y [4]

Answer:

The outcome variable type (continuous, binary, or time -to- event)

Explanation:

The outcome variable type is the type of variables involved in a research. The researcher would put the type of variable involved in his research into consideration in deciding what regression model to apply in his research. For example, if the type of variable in his research are continuous variables(continuous variables are variables that may be any value within a range and may be infinite), he would use linear regression

4 0

3 years ago

Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

4 years ago