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lesya692 [45]
3 years ago
7

HELP PLEASEEEEEEEE!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
mariarad [96]3 years ago
7 0
Plus or minus 3. (The 1st answer)

x^2 means (-3*-3) which equals 9

x^2 means (3838) which also equals 9

6*9=54

Maksim231197 [3]3 years ago
7 0
First u would divide by 6 on both sides to get the x by itself and you would get x squared is equal to 9. Then u would take the sqaure root of both sides because u want to get rid of the squared and a sqaure root un do's that. After square rooting both sides you would get x = 3 because the square root of x squared is x and the square root of 9 is 3. so the answer is Plus or minus 3 or the first choice. Its also plus or minus because two negative 3's would give you nine and two positive 3's would give u 9.
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Find the upper 20%of the weight?
meriva

Answer:

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Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - \mu}{\sigma}

X = 0.84\sigma + \mu

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

6 0
3 years ago
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